北大数学物理方法(B)教案04Cauchy 积分公式

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WuChong-shi()Cauchy1()Cauchy§4.1CauchyCauchyf(z)!G#$%&’()*+G$,-C./0123+a4G567+8f(a)=12πiICf(z)z−adz,9#:.;3C$=?@AG5BC|z−a|r(DE4.1+FGCH|z−a|=rAG5)+8IJKLM!$CauchyNO+PICf(z)z−adz=I|z−a|=rf(z)z−adz,Q4.1RSTUVCauchyWXYZ[\]^_r$‘abc+defr→0?g4limz→a(z−a)f(z)z−a=f(a),hiO3.1+jkl12πiICf(z)z−adz=f(a).WuChong-shi§4.1Cauchy2mCauchynob-!+pqrf(z)As%tuvwCxyCz({|b}~7)%&’(?+A12πiICf(z)z−adz,9#a4Cz67+:.;3C$+b}~7$=+E4.2?ACzB674C+R4$‘CCR++noCCR{v$KLM!+IJP-!$Cauchy:.+PQ4.2STUVCauchyWXYZ12πiICRf(z)z−adz+12πiICf(z)z−adz=f(a),:.;3CR$?qR‘+\]¡j_R$¢£‘abc+o+efR→∞+⁄l¥12πiICf(z)z−adz=f(a)−limR→∞12πiICRf(z)z−adz.]f(z)ƒ§¤'iO3.2$q“+8e«‘CCR$:.$‹›&+limR→∞12πiICRf(z)z−adz=K,K=limz→∞z·f(z)z−a=f(∞).g[+12πiICf(z)z−adz=f(a)−K.fiflK=0+jl¥mCauchy]f(z)As%tuvwCxyCz’(+–z→∞+f(z)6†‡o0+8Cauchy:.f(a)=12πiICf(z)z−adz·¡¶+[•a4Cz67+:.;3C4?WuChong-shi()Cauchy3§4.2‚„”»…‰¿»Cauchy:.+e`´«6ˆq\˜]f(z)AG#’(+8AG5f(z)$¯˘˙¨*f(n)(z)˚A+¸–f(n)(z)=n!2πiICf(ζ)(ζ−z)n+1dζ,9#CG$=,-+z4G5¯67+E4.3?@˝˛“f0(z)?g4f(z+h)−f(z)h=12πi1hICf(ζ)ζ−z−h−f(ζ)ζ−zdζ=12πiICf(ζ)(ζ−z−h)(ζ−z)dζ,Q4.3ˇ—YZ‹›h→0+4f0(z)+⁄:)*$‹›4f(ζ)/(ζ−z)2?4kA:.“‹›u+ICf(ζ)dζ(ζ−z−h)(ζ−z)−ICf(ζ)dζ(ζ−z)2=hICf(ζ)dζ(ζ−z−h)(ζ−z)2.hof(ζ)ACxLÆ+dACxP|f(ζ)|≤M+z¥C$ª4δ+l4C$+8P ICf(ζ)(ζ−z−h)(ζ−z)dζ−ICf(ζ)(ζ−z)2dζ ≤|h|·Mlδ2(δ−|h|)→0,g[+:.“‹›u+f0(z)=12πiICf(ζ)(ζ−z)2dζ.Ł+e“«f00(z)=limh→0f0(z+h)−f0(z)h=limh→012πi1hICf(ζ)(ζ−z−h)2−f(ζ)(ζ−z)2dζ=limh→012πiIC2ζ−2z−h(ζ−z−h)2(ζ−z)2f(ζ)dζ=2!2πiICf(ζ)(ζ−z)3dζ.[ØÆ+e“«f(n)(z)?F\]Œ+6Kº)*+qA6!#6˙¨*••˚A(æı)+8$¯˘˙¨*ł˚A+¸–ł!5$’()*?FAøº)*#¸œ[?߸hf0(x)$˚A`´«f00(x)$˚A?FKº)*#f(z)A6!#••e¨(’()6$q“?øº)*#f0(x)$˚A{xA*x(6N!5)ºnf(x)$q“+⁄Kº)*#f0(z)$˚A8{A!xnf(z)$q“?WuChong-shi§4.3Cauchy4§4.3Cauchy…‚„Ax6co’()*˙¨*$k#+f(z)$’(£A(1)f(z)eCauchy:.(2)f(z)ACxLÆ?g[+ˆKx$+jekA6!./01$(tutu)23CxLÆ$)*φ(ζ)#$:.f(z)=12πiZCφ(ζ)ζ−zdζ($4Cauchy%)23z7z$’()*+f0(z)eM:.“¨⁄l¥+f(p)(z)=p!2πiZCφ(ζ)(ζ−z)p+1dζ.&:.f(z)=12πiI|ζ|=1ζ∗ζ−zdζ,|z|6=1.’6Cauchy(:.?g4A|ζ|=1xζ∗=1/ζ+df(z)=12πiI|ζ|=11ζ(ζ−z)dζ.|z|1+[:.eCauchy:.+f(z)=12πiI|ζ|=11ζ1ζ−zdζ=−1z.0|z|1+f(z)=12πiI|ζ|=11z1ζ−z−1ζdζ=0.)*+«+[\]noz=0·¶?,ux\]+jPf(z)=12πiI|ζ|=1ζ∗ζ−zdζ=−1z,|z|1,0,|z|1.h[eD+f(z)A|z|6=1•’(+-.ζ∗A/’(?WuChong-shi()Cauchy50Cauchy(:.+je`«123’45?674.21.f(t,z)t8z9:ı+t∈[a,b]+z∈G+2.;[a,b]=?t@+f(t,z)G=A@ı+8F(z)=Zbaf(t,z)dtAG5’($+–F0(z)=Zba∂f(t,z)∂zdt.@g4f(t,z)AGx’(+dnoG5$¯˘67z+Cauchy:.¶+f(t,z)=12πiICf(t,ζ)ζ−zdζ.BCF(z)$ND+¸EF:.GH(g4f(t,z)LÆ)+lF(z)=Zbadt2πiICf(t,ζ)ζ−zdζ=12πiIC1ζ−zZbaf(t,ζ)dt#dζ.6Cauchy(:.+Zbaf(t,z)dtLÆ+dF(z)4G5$’()*+–F0(z)=12πiIC1(ζ−z)2Zbaf(t,ζ)dt#dζ=Zba12πiICf(t,ζ)(ζ−z)2dζdt=Zba∂f(t,z)∂zdt.I¡+\˜JKoZCf(t,z)dt?^q“C./0123+tACxºL+z∈G+f(t,z)tz$LÆ)*?k$_xMŁ?WuChong-shi§4.1NOPO6(Q)RSTUVWX+YZ[X+ı\]^_‘abcd?efghı8Yiıjk[Xlm?noıXpq8roıstuv8wxyz?§4.1{»|»6}K*~*u0+u1+u2+···+un+···=∞Xn=0un.fun$ø.fl4αn_βn,8∞Xn=0un=∞Xn=0αn+i∞Xn=0βn.6K*~*Pun/oø*~*PαnPβn+¡?]~*$.Sn=u0+u1+u2+···+un#$H{Sn}+8$~*Pun+H{Sn}$‹›S=limn→∞Sn+$4~*Pun$∞Xn=0un=limn→∞Sn.8+~*Pun$?~*$+$.H$ND$?g[+IJH$q!+e«~*$q!Cauchyq!lε0+n+;p+|un+1+un+2+···+un+p|ε.fifl+fp=1+jl¥~*$¡q!limn→∞un=0.FA¢º“GH$£⁄+e¥~*¸ƒ?u1+u2+u3+u4+···=(u1+u2)+(u3+u4)+···.WuChong-shi(§)¤'PO7F]~*∞Pn=0|un|+8$~*∞Pn=0un“n?“n$~*6N$?|un+1+un+2+···un+p|≤|un+1|+|un+2|+···+|un+p|.+6$~*+«6N“n$?F“n~*$‹fl?F›fifl–†|un|vn+⁄∞Pn=0vn+8∞Pn=0|un|∞Pn=0un“n?†|un|vn,⁄∞Pn=0vn+8∞Pn=0|un|?F›‡fl–†˚A_nbc$·*ρ+8 un+1un ρ1+~*∞Pn=0un“n un+1un ρ1+~*∞Pn=0|un|?•s@Zx¶•;ef‚kX+„b|un+1/un|ab””^sunab»A…f+‰ks@Zx¿`´ˆP|un|˜¯˘?•ρ˘˙•¨w˚¸k˝˛ab+ˇd’AlembertZx?Fd’Alembertfl–]limn→∞|un+1/un|=l1,8∞Pn=0un“n]limn→∞|un+1/un|=l1,8∞Pn=0|un|?•d’AlembertZx¶•d—+=˝˛^ss@Zxρ…»A?•d’AlembertZx•kzZX˜¯8+ˇklimn→∞|un+1/un|ˆX∞Pn=0|un|˜¯+klimn→∞|un+1/un|ˆX?;limn→∞|un+1/un|≥1limn→∞|un+1/un|≤1aƪˆ+limn→∞|un+1/un|=limn→∞|un+1/un|=limn→∞|un+1/un|.•CauchyZx¶•ÆŁzdŁlimn→∞|un|1/nˆXØŒ;˜¯?FCauchyfl–]limn→∞|un|1/n1,8~*∞Pn=0|un|]limn→∞|un|1/n1,8~*∞Pn=0un?WuChong-shi§4.1NOPO8º51.¢FGH?u0+u1+u2+u3+u4+···=u0+u1+u2+u4+u3+u6+u8+u5+···.2.e6“n~*æ~*+~*·“n?∞Xn=0un=∞Xn=0u2n+∞Xn=0u2n+1.3.“n~*:·¡“n+Xkuk·Xlvl=Xk,lukvl.$:6ˆ~*u0v0+u0v1+u0v2+u0v3+···+u1v0+u1v1+u1v2+u1v3+···+u2v0+u2v1+u2v2+u2v3+···+u3v0+u3v1+u3v2+u3v3+···+···.9“nıeł¯H“+9&º?ek+l=n$‘aHø+∞Xk=0uk·∞Xl=0vl=∞Xn=0wn,wn=nXk=0ukvn−k.]›oœ“GH(œ“GH¢Pfiß$ˆq)+8$!ePuk,Pvlł+–9#6“nPuk,PvlPwnł?WuChong-shi(§)¤'PO9§4.2”»|»5uk(z)(k=1,2,···)A!G#PND?]noG#67z0+~*∞Pk=1uk(z0)+8$~*∞Pk=1uk(z)Az07?+]∞Pk=1vk(z0)+8$~*∞Pk=1vk(z)Az07?]~*∞Pk=1uk(z)A!G567ł+8$~*AG5?9)*S(z)G5$%&)*?5]no¯N$ε0,˚A6_zbc$N(

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