华北理工环境工程原理习题及解答第2章 质量衡算与能量衡算

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12.1O30.08×10-611.013×105Pa25g/m320.83×105Pa15O31molV1V0·P0T1/P1T022.4L×298K/273K24.45LO30.08×106mol×48g/mol×24.45L1157.05g/m321molV1V0·P0T1/P1T0=22.4L×1.013×105Pa×288K/(0.83×105Pa×273K28.82LO30.08×106mol/28.82L2.78×109mol/L2.2251.013×105PaSO2400g/m30.14×10-6SO233965108.31429810400100.15101.0131064AARTpM2.3SI1.5kgf·s2/m=kg13.6g/cm3=kg/m3235kgf/cm2=Pa4.7atm=Pa670mmHg=Pa10kW2Btu/(lb·)=J/kg·K3kcal/kg·=J/kg·K2.5L/s=m3/h70dyn/cm=N/m5kgf/m=N/m1.5kgf·s2/m=14.709975kg13.6g/cm3=13.6×103kg/m335kg/cm2=3.43245×106Pa4.7atm=4.762275×105Pa670mmHg=8.93244×104Pa107.4569kW2Btu/(lb·)=8.3736×103J/kg·K3kcal/kg·=1.25604×104J/kg·K2.5L/s=9m3/h70dyn/cm=0.07N/m5kgf/m=49.03325N/m2.40+At——tlb/ft30——t0lb/ft3t——AAkg/m3·K32.5O20.21,N20.79O2N2CO20.07H2O0.14O20.056N20.734100m330m3300N2N2V20.79×P1V1/RT10.734×P2V2/RT20.79×100m3/303K0.734×V2/573KV2203.54m32.636000m3/d3.0mg/L10000m3/d30mg/L12kg11122123.0360003010000/8.87/3600010000VVmVVqqmgLmgLqq2312()8.87(3600010000)10/408.02/mVVqqkgdkgd2.710×106m350m3/s5m3/s100mg/L0.25d1mm4120mmqqkV5×100mg/L550mm3/s10×106×0.25×mm3/s0m5.96mg/L2.83.0m3/s0.05m3/s1.0mg/L0.0530.05×1.061mg/L61×0.05g/s3.05g/s2.9100km1.0km4m/s10.0kg/s0.20h1121m/s2h110.0kg/s0.20/3600××100×100×1×109m3/s4×100×1×106m3/s051.05×10-2mg/m32Lhqmu12mtmmdqqkVd22tmdquLhkLhLhd23600-6-501.0510t106.610dd1.15×10-2mg/m32.101m320mg/L10m3/min2mg/L5mg/L00tVVdVqqd1t10(2)dd50201t10(2)tddt0.18min62.111m3m4cmu0zu00.622gz0.51m3A1A2A2u0dV/dtu0dz/dt×A1/A2dz/dt×100/420.622gz0.5226.55×z-0.5dzdtz03mz1z01m3××0.25m2-11.73mt189.8s2.12150kg/h30kg/h120kg/h100kg1htdtd3012010060tdtd30×dt10060tdC120Cdt30120Cdt10060tdCt0C07t1hC15.232.134×3m23000kJ/m2·h500.8L/min1h3000×12×50kJ/h18000kJ/hTmpqcT18000kJ/h0.8×60×1×4.183×TkJ/h.KT89.65K2.141000MW2/3100m3/s201102Q1000×2/3MW667MW1VqmpqcTVq×103×4.183×10kJ/m3667×103KWQ15.94m3/s28100×103×4.183×TkJ/m3667×103KWT1.59K

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