华北理工环境工程原理习题及解答第5章 质量传递

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15.1298K0.1×106pa298KL20cm0.1×106Pa298KDAB2.50×10-5m2/s298K3.1684×103PapA,i3.1684×103PapA,00,0,5,,0,-0.984110PalnBBiBmBBippppp1,,042A,-N1.6210molcmsABAiABmDpppRTpL282,,05.1110molcmsPaAGAiANkpp3,0,,1111zLAAAiAiyyyyyA,i3.1684/1000.031684yA,00(15z)Ay10.96835.22.026×105Pa298KABApA,10.4×105PapA,20.1×105Pak0G1.26×10-8kmol/(m2·s·Pa)ABkGNA2,1,200,1,2ABAAAGAADppNkppRTL,1,2,1,2,ABAAAGAABmDpppNkppRTpL0,1,2,AGAABmpNkppp,2,15,,2,11.7510PalnBBBmBBppppp0,GGBmpkkp=1.44×10-5mol/(m2·s·Pa)2,1,20.44molmsAGAANkpp5.35mm4mm30DAB0.11m2/h.1.01×105Pa,,0,ABAiAABmDpppNRTpz304.2474×103Pa995.7kg/m3995.7×103/180.5532×105mol/m330DAB0.11m2/hpA,i4.2474×103PapA,003,0,5,,0,0.988610PalnBBiBmBBipppppNAcV/(A·t)(4mm)cV/(A·t)DABp(pA,ipA,0)/(RTpB,mz)t5.8h5.85.430mm298K301.01×105Pa10mm2d298K0.26×10-4m2/s253.1684×103Pa995.7kg/m3c995.7×103/180.5532×105mol/m330DABD0(T/T0)1.750.26×10-4m2/s×(303/298)1.752.6768×10-5m2/spA,i3.1684×103PapA,00pB,m(pB,0pB,i)/ln(pB,0/pB,i)0.99737×105PaNAcdV/(A·dt)cdz/dtcdz/dtDABp(pA,ipA,0)/(RTpB,mz)t10z1z00.01t22d,z2zz2243600,,00.010,()ddABaiaBmDpppzztRTpcz0.0177mzzz00.0077m7.7mm5.5295K41mm6.6×103N/m20.236×10-4m2/spB,1,pB,2pB,mB,2B,15B,mB,2B,1ppp0.9796310PalnppABA,1A,222AB,mDpppN6.5710molmsRTpL5.62m0.15mm1.01×105Pa293K1.8×10-5m2/s12h20P=2.69×105x(Pa)xag0.1a/17mol(0.9a/180.1a/17)mol0.1a17x0.10530.9a180.1a17p0.1053×2.69×105Pa0.2832×105PapA,i0.2832×105PaPA00B,0B,i5B,mB,0B,ippp0.860810PalnppABA,iA,022AB,mDpppN4.9110molmsRTpL523Adn=Nt6.6610mol45.7251.013×105Pa0.1cm7min0.054cm1.5×10-3mol/LcA,GdV/dtk(cA,scA)Adr/dtk(cA,scA)/cA,GcA,s1.5×10-3mol/LcA0cA,Gp/RT1.013×105/(8.314×298)mol/m340.89mol/m3dr0.03668k×dtt10r15×10-4mt2420sr22.7×10-4mk1.49×10-5m/s5.83min50a0cA,SAV,d(VcA)/dtk(cA,ScA)AaA/VdcA/dtkacA,ScA6t0cA0cA/cAS1e-kat1131AA,Sc0.5ka=tln1180sln13.8510sc15.9AB1.013×105Pa278KS0.1mPA1=1.34×104PaPA2=0.67×104Pa1.85×10-5m2/sAB1BS2ABS1BSApB,1ppA,187.9kPapB,2ppA,294.6kPaB,2B,15B,mB2B,1ppp0.912110PalnppDAB1.85×10-5m2/sABA,1A,242AB,mDpppN5.9610molmsRTpL2ABSABA,1A,242ADppN5.3610molmsRTL

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