上海交通大学硕士学位论文连锁超市配送中心绩效评价体系设计及应用姓名:李燕蕾申请学位级别:硕士专业:物流工程指导教师:潘尔顺;刘伏生20081001IIIIIIVDESIGNANDAPPLICATIONOFTHEPERFORMANCEEVALUATIONSYSTEMINDISTRIBUTIONCENTEROFCHAINSUPERMARKETABSTRACTThereisincreasingcompetitioninchainsupermarketgoingwiththerapiddevelopment.MoreandmoremanagementrealizethatthelogisticsisthemostimportantforthedevelopmentofchainBusinessCorporation;aneffectivedistributionsystemisakeyfactortoenhancethecore-competitionofchainBusinessCorporation.Meanwhile,theDistributionCenter(DC)takesthemostresponsibilityofprofessionalmanagementofthelogistics.HowtogettheoverviewoftheoperationofDC?HowtoevaluatetheperformanceofDCfullyinasystematicalway?ThesearedeeplyconcernedpointsforthedevelopmentofDC.Baseonthebackground,thispaperanalyzesthecurrentlogisticalperformanceevaluationmethod,samplesthedatafromDCanddesignsaperformanceevaluationsystemforDC.ThissystemcouldsupportthedevelopmentofDCfully.VFirstofall,thepreliminaryindexsystemisstructuredaftertheacquisitionoftheevaluationindexsystem,whichisbasedonthesummarizingoftheexistingindexsystem.Afteranalyzingthequestionnaireandfilteringtheindex,thefinalindexsystemisestablished.Secondly,whileconfirmingthemethodsofperformanceevaluation,thispaperintroducesAnalyticalHierarchyProcessandthefuzzycomprehensiveevaluation.Meanwhileusingthejurisdictiondegreetheoryinfuzzymathematics,thejurisdictiondegreemodelsthatarefilledwithquantitativeindexesissetup.Finally,thispaperpracticestheindexsystemandtheevaluationmethodforsomechainsupermarketDC,andcalculatestheweightofallindexes.Basedontheactualdata,thejurisdictiondegreeofquantitativeindexesisconfirmedseparately.Atlast,usingthefuzzycomprehensiveevaluation,reasonableevaluationresultsisgot,includingeachdepartment,activityandperiod.KEYWORDS:chainsupermarket,DistributionCenter(DC),performanceevaluation,evaluationsystem11.11.1.1199470%199919995034%74[1]2000111.420010105120014.3%200510%2005200116713.41313821.92162024053580496870754.36.07.89.310.502000400060008000200120022003200420050.02.04.06.08.010.012.0%(10105fig1ThepercentageofsalesofChainBusinessCorporationtop100inthetotalconsumergoodsretailsalesfrom2001to200520061005296206.954575195210021400008125%,1.1.231.2341.1.3Wal-martWal-mart51.21.2.1121.2.2262fig2Theframeofdissertation1.2.31Internet2zzzzzzzz731.382.1[2]2.22.2.119920190319231929193320802011921932010()42090ABC52090,SinkandTuttleSinkandTuttle()()()()(PIMMPerformanceImprovementMeasurementMethodology)PIMM(FamilyofMeasures)112090(BalanceScorecardBSC)19922.2.21990Nevemworkinggroup()[3]1994Chowetal.,CaplineSheer1.2.3.[4][5]A.F.ThomasH.L.Richardson(berlchmarking)12DareR.Hull[6][7][8]2.32.3.1209019921993199319951993()131019938199963242002232282.3.214[9](1)(2)(3)(4)[10][11]7()[12][13][14](1)15(2)(3)(1)[15]16[16](2)[17][18](3)AHP[19](4)[20](DEA)DEA[21]DEADEAAHPDEAAHPAHPDEAAHPDEAAHPDEAAHP(1)17(2)DEA[22]2.4183.13.1.1()(GB:2001.8.1):():::19()::a)b)c)d)e)f)3.1.2[23]1.2.203.4.5.6.7.3:213fig3ThegeneralflowchartofDistributionCenterofChainSupermarket3.1.3()22[24]3.2[25](1):(2)(3)3.34234fig4Theprocessofevaluationindexsystemestablishing3.4243.4.1()1.2.3.4.25×100%=3-113.4.21.×100%=3-22.26×100%=3-33.4.−×100%=(3-4)5.×100%=(3-5)6.2273.4.31.+=2(3-6)2.28=(3-7)×=360360=(3-8)3.100%×=(3-9)=++4.−×100%=(3-10)5.29×100%=(3-11)6.×100%=(3-12)7.=++(3-13)8.×100%=(3-14)3303.4.41.×100%=(3-15)2.×100%=(3-16)3.×100%=(3-17)4.×100%=(3-18)5.31×100%=(3-19)6.×100%=(3-20)43.5103213-155432112714.1234343284.24824.85734.76644.673614.28343491453.61013333.211823.812644.6134514.3143614.2155414.41625213.817134113.2181453.61926113.920464.421554.522464.4234334.1243343.944335fig5Themodelofperformanceevaluationindexes343.6,354.1AHP(AnalyticalHierarchyProcessAHP)A.L.Satty207080AHP()1.()[26]123634AA=W*maxmaxAWmaxW()2.:1AHP69376fig6Hiberarchymodel2AHPU1,U2,UnUiUjA=aijnnaijUiUjC6135792468A1)aij02)aij=1/aji3)aii=1n()(1)2nn−12k12m12n383AAHPAAAmax=nmax11niiw==∑12(,,...,)Tn=,w,U1,U2,...UnCmaxnwU1,U2,...Un1maxnCInλ−=−4-1CI=0CIARIn=3-11RI[19]7n34567891011RI0.520.891.121.261.361.411.461.491.52CR:CICRRI=(4-2)CR0.14AHP()nAmA1,A2,Ama1,a2,amBnB1,B2,39BnAjb1j,b2j,bnjBkAibkj0B88A1A2…AmABa1A2…amBB1b11B12…b1m11mjjjab=∑………………Bnbn1bn2…bnm1mjnjjab=∑4.24.2.1[27]U={u1,u2,un}V={V1,V2,,Vm}R401111212122212.........................................................mmnnnnmRRRrrrrrrrrr==4-3Ri=(ri1ri2rim)(i=12n)uiVrijuiVj(j=12m)W=(w1w2wn)UB=(b1b2bm)=WR=(w1w2wn)111212122212.....................mmnnnmrrrrrrrrr4-44.2.241B=WR=W11111212111212122222221122nmmmmnnnnnmnmWRWRWWRWRWRWWRWRWRWWR⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅⋅4-54.3[27]1.C()ÃÃ0101[0,1]42Cc∈ Ã()Cµ0cÃ() [] []ÃÃ01()01:CCCµµ00→→∈Ã()01[0,1]Cc∈ Ã()Cµcà [] []ÃÃ01()01:CCCµµ→→∈Ã[28]2.()()r=i0()inf()()sup()1()inf()nf()()sup()sup()inf()afxffxffxfffxfff≤≥−≤≤−(4-6)r=i1()inf()()sup()0sup()()nf()()sup()sup()inf()afxffxfffxffxfff≤≥−≤≤−(4-7)43f(x)sup(f)inf(f)f(x)a=1[0,1]4.4445.1525.1.153-284.1[19]maxλnCR0.1459maxλmax1CInnλ−=