高频电路(张萧文版)第五章课后习题答案

得到近似线性特性。可只取其级数的前两项线弯曲部分，故围内变化，不会进入曲号电压在特性的线性范勒级数原则，可认为信很小时，根据泰部分，然后当在抛物线上段接近线性较大时，静态工作点选即当，似当成线性元件来处理，该非线性元件就能近时，当解：m000200022200202002VVcos22cos2121cos2cos85tVVVkiVVtVVtVVVktVVkkvimmmmmmBZmBBmBBBZooCCVVVVVVi212160cos60125。应为最大值，中的二次谐波振幅达到解：为了使为奇数为偶数当当解：nnngVttdntgVIgVttdgVIgVttdgVItnIitttgVimmnmmmmnnm0112coscos121cos11cos21cos0cos00coscos13522100,3,2,1ktcos2k12k1gV4gV2i0cos00coscosi0cos00coscosiii15501k21kmmD2D1D2D1tttgVtttgVimm当当当当解：,3,2,1k142cossin2142cos2sin12isinsin10sinsin100sinsin11651201200000000kkktkωΩtmktkωΩtmgVttmgVittmVittmV时，当；时，解：当21L221221LD2D1L0vv4kRvvkvvkRiiRv175解：2123213221221103213221221103213221221103213221221103142143208185vvbRvvbvvbvvbbRvvbvvbvvbbRvvbvvbvvbbRvvbvvbvvbbRiiiiRiiRiiRvLLLLLLLL解：31310440330220302000cos0304021304021003040304020300210330402203002134232116322183cos6cos2coscoscos61cos21cos1coscos25.121323coscoscos22cos123cos2cos4cos3cos24321235000kTqVIkTqVIggkTqVIkTqVIgtkTqVItkTqVItkTqVItkTqVItVkTqtVkTqtVkTqtVkTqaIetVkTqaIdvditgevkTqaIdvdigVbVbggVbVbgttVbtVbVbtVbbtVbtVbtVbbdvditgvbvbvbbdvdigomSomSmcomSomSmomSomSomSomSomomomomStVkTqomSvvBECmvkTqBESBECmmmmcmmmmmmmmmmvvBECmBEBEBEBECmomBEBEBE解：03430402404303202010404303202010404303202010404303202010423116168255vvavvavvavvavvavvavvaavvavvavvavvaavvavvavvavvaavvavvavvavvaaiiiiisssssssssssssssssss解：dBfQfAQQAAdBgggASggmSIggmSIrIIgipcLpcpcociccpcceocEebicEbbETsEc1.30122810100465211047322114010473004.055.046.94455.035265.0266.9265.05.0265.0261265.0295227.00max20max22max02解：dBgGGggAdBgggASggmSIggmSIrIIgicLLoccpcociccpcceocEebicEbbETsEc231961.01.01.001.054.1289.59201.01.0454.14101.0302608.02654.12608.05.0265.0261265.03052222max02解：03430402404303202010404303202010404303202010404303202010432116168325vvavvavvavvavvavvavvaavvavvavvavvaavvavvavvavvaavvavvavvavvaaiiiiisssssssssssssssssss解：扰。信号，则能产生阻塞干互调干扰；若有强干扰，可能产生生交调干扰；有二次项不存在三次项，不会产时产生镜像干扰。由于就会产生中频干扰；当进行混频。只要满足解：因存在二次项，能i0ninfffff345，合理选择中频等。提高前端电路的选择性时产生。、、、的哨叫声在附近，和波段内的干扰在的情况。所以落于数，不考虑大于为本振和信号的谐波次、，因最终出现哨叫声。差拍检波，产生音频，的非线性效应，与中频通过检波器放大后加到检波器上，进入中频放大器，并被它就能和有用中频一道的通带内，合频率接近于中频放大组合频率，如果这些组还存在一些谐波频率和中频电流外，输出电流中，除需要的扰。这是由于混频器的此现象属于组合频率干解：.31396kHz1394kHz931kHz929kHz1kHz1395kHzf930kHzf1605kHz~5353qp465kHzf.2.1355SSi。谐波较小，可以不考虑大于、，会产生互调干扰；，、，会产生互调干扰；，、，会产生互调干扰；，、，会产生互调干扰；，、，会产生互调干扰；，、，会产生互调干扰；，、，不会产生互调干扰；，、，则会产生互调干扰：解：若满足3qpMHz5.42710357743ff33q3pMHz4.3921035277432f3f2q3pMHz4.6531035377423f2f3q2pMHz3.61810357742ff22q2pMHz2.58310357742f2f1q2pMHz2.844103527742ff2q1pMHz1.8091035774ff1q1pfqfpf36521212121212121s21MHzfMHzfMHzffffffMHzffffffMHzfMHzfMHzffffffMHzffffffSssssssSSSSSSS16420302302123032302326.02.04.0232228.0232223137500000000000000解：。，故没有互调信号输出、、已知，则会产生互调干扰。解：若满足MHz20323fff2MHz.19f6MHz.19ffqfpf395i0s21s21