桥梁桩基施工后不满足设计要求时的验算和处理

1NO.120043journalofguangdongcommunicationpolytechnicMarch.2004201671-8496(2004)01-0020-03121.5104202.510620U445ACheckingComputationsandDisposalWhentheBasicConstructionoftheBridgeDoesn’tmeettheNeedoftheProjectCHENYu1,WANGNing2(1.GuangdongGuangshaoHighway.Ltd,Shaoguang510420,China;2.ChangDaroadandbridgelimitedcompanyofGuangdongprovince,Guangzhou510100,China)Abstract:Thisarticleisaboutthecheckingcomputationsanddisposalwhenthebasicconstructionofthebridgedoesn’tmeettheneedoftheproject.Keyword:Bridge;Basic;Checking-computations;Disposal1K251+900K301+14055.232219777045342K259+116.53-13U1#2#1250KPa341#2#ö1.21#16.52#181#2#2004-01-13(1974-)1NO.120043journalofguangdongcommunicationpolytechnicMarch.20042115181#16.5A[P]=1/2ulii+ëm0A[(0)+k2r2(h-3)]=0.7m0=0.70=500kPak2=1.5r2=17[P]=1/2×1.2××(2.5×50+10.5×50+3.5×80)+0.7×0.7×/4×1.22×[500+1.5×17×(16.5-3)]=2221KNB712KN2×571.5KN173.5KN:98KN1/2233KNP=712+2×571.5+173.5+98+233=2360KN[P]P2360-2221/2360×100%=5.9%+[0]=200250kPa15.71×3.822AP1=1414.5(KN)P2=1414.5(KN)P3=2126.5(KN)M=(2126.5-1414.5)×6.775×1.4=6733.4KN·MW=1/6ab2=1/6×3.8×15.712=156.3m3max=N/A+M/W=(4955.5×1.3)/(15.71×3.8)+6733.4/156.3=151kPa[0]B30%P=550×0.3=165(KN)12,1P/2=82.5KNM=82.5×(6.5+2)×1.4=982KNW=1/6ab2=1/6×15.71×3.82=37.81(m3)max=N/A+M/W=(1414.5×3×1.2+712×3)/(15.71×3.8)+982/37.81=147(kPa)[0],=12+221/2=1472+15121/2kPa=210.7kPaC0=200KPa[]=[0]+k1r1(b-2)+k2r2(h-3)=200KPa+2.5×19×(16.5-3)=841KPa[]=[200×(15.71×3.8-÷4×1.22×3)+841×÷4×1.22×3]÷(15.71×3.8)=236.4KPa[ä0]=200KPa2#18A[P]=1/2ulii+m0A[(0)+k2r2(h-3)]=0.7m0=0.70=500kPak2=1.5r2=17[P]=1/2×1.2××(2.5×50+10.5×50+5×80)+0.7×0.7×/4×1.22×[500+1.5×17×(18-3)]=2468(KN)B415.71m1NO.120043journalofguangdongcommunicationpolytechnicMarch.20044130mm5.0m4.8m23cm20cmÖ130mm1276ZK129+124ZK129+116ZK129+1362.0m22ZK129+544ZK129+740ZK129+544ZK129+634ZK129+655ZK129+740ZK129+530ZK129+7602.0m232ZK129+853ZK129+841ZK129+8612.0m222168YK130+196YK130+216YK130+396YK130+416YK130+635YK130+6553332.0m66YK130+450YK130+6003.0m10234442235137.9m3/211.59m3/53.4104m3/128m3/23.1[1]..199721712KN2×571.5KN173.5KNð/4×1.02×5×25=98(KN)1/21/2×ð/4×1.22×18×25=254KNÓP=712+2×571.5+173.5+98+254=2381(KN)[P]ÓP61#2#m3/%115.78156.7335.322.1254.86148137.9211.5953.4384826.3668021.210412823.1