直埋热力管道应力计算

管道外径D(m)0.325管道壁厚d(m)0.014线性系数α(m/(m•K))0.0000122弹性模量E(Pa)1.98E+11摩擦系数μ0.4工作温度t1(℃)95安装温度t2(℃)0泊松系数ν0.3增强系数n1.3截面积A(m2)0.01367156二次矩I(m4)0.00054667管道重量g管（N/m)706.3介质重量g介（N/m)681保温厚度d0(m)0.05土壤密度γ(N/m3)17000设计压力Pa(MPa)1.6屈服点σs(MPa)235许用应力σ(MPa)130μγ(kg/m3)D0(m)g管（N/m)g介（N/m)D(m)d(m)0.4170000.425706.36810.3250.014Hkp(m)g(kN)1.3911.431.3911.43t1(℃)t2(℃)E(Pa)α(m/(m•K))D(m)d(m)μ9501.98E+110.00001220.3250.0140.4Lf(m)f(N)F(kN)29.71105.613137.3829.713137.38105.61t1(℃)t2(℃)E(Pa)α(m/(m•K))nσs(MPa)ν9501.98E+110.00001221.32350.3σt(MPa)dTg(℃)dT(℃)18.57121.0995.0095.00121.0918.57t1(℃)t2(℃)E(Pa)α(m/(m•K))nσs(MPa)ν9501.98E+110.00001221.32350.3管道稳定性计算摩擦长度(m)实际温差(℃)屈服温差(℃)环向应力(MPa)热屈服温差临界最小覆土深度临界最小覆土深度(m)管道上部重力之和(kN)管道特性值土壤横向压缩反力系数C(N/m3)3500000请输入数据单位长摩擦力(kN/m)轴向推力(kN)摩擦长度土壤摩擦力计算管道过渡段长度计算管道过渡段长度计算管道热屈服温差计算L(m)dT(℃)A(m2)28.9995.000.013728.99105.610.0137t1(℃)t2(℃)E(Pa)α(m/(m•K))f(kN/m)L(m)dTg(℃)9501.98E+110.0000122105.6128.99121.09dL1(mm)dL2(mm)15.2315.2315.2315.23t1(℃)t2(℃)C(N/m3)D(m)E(Pa)I(m4)95035000000.4251.98E+110.000547L1(m)L2(m)9.509.509.50t1(℃)t2(℃)E(Pa)α(m/(m•K))νdTg(℃)σt(MPa)9501.98E+110.00001220.3121.0918.57Na(kN)dT(℃)A(m2)3061.2195.000.01373061.21t1(℃)t2(℃)E(Pa)α(m/(m•K))νσt(MPa)9501.98E+110.00001220.318.57σp(MPa)dT(℃)A(m2)-216.4895.000.0137-216.48不需要校验过渡段长度，直管段中可以有锚固段存在30.05当量应力变化范围(kN)管道锚固段轴向力计算管道锚固段内轴向力计算过渡段校核长度(m)管道过渡段伸长量计算管道过渡段伸长量计算L\Z\π型管道转角臂长计算臂长度(m)管道锚固段内轴向力计算锚固段轴向力(kN)热伸长量(mm)塑性状态下热伸长量(mm)管道锚固段轴向力计算臂长计算管道过渡段长度计算过渡段长度(m)单位长摩擦力(kN/m)横截面积(m2)α(m/(m•K))E(Pa)t1(℃)t2(℃)0.00001221.98E+11950γ(kg/m3)17000Pa(MPa)D(m)d(m)1.60.3250.014Pa(MPa)D(m)d(m)μγ(kg/m3)dTg(℃)1.60.3250.0140.417000121.09热屈服温差临界最小覆土深度摩擦长度管道过渡段长度计算过渡段：如图中的AB段，当介质温度发生变化时，设置补偿器A点处的管道处于自由伸缩状态，管道截面位置由A点逐渐移向B点，由于管道与周围土壤摩擦力f作用，使得管道热伸长受阻，当B点处的摩擦力增加到与温度胀力相等时，管道就能不再向有补偿器的A点处伸长，而进入了自然锚固状态。在这类管段中，管道的热伸长由A点自由伸缩逐渐过渡B点的锚固状态，管道的轴向温度应力亦从A点处为零逐渐增加到B点处最大值，各处管道都有不同程度的热伸长。这种管段的设计计算的主要任务是计算管段的热𝐻𝑘𝑝=𝐾−𝑔管−𝑔介𝐷𝛾𝐾=0.081𝛼1.83E𝐴1.5𝑡1−𝑡21.83𝜇0.33𝐼0.5𝑓=9.8𝜇𝜌𝐻+𝐷2𝜋𝐷𝐿𝑓=𝐸𝛼𝑡1−𝑡2𝐴9.8𝜇𝜌𝐻+𝑑𝑦2𝜋𝑑𝑦Δ𝑇𝑔=1𝛼𝐸𝑛𝜎𝑠−1−𝜈𝜎𝑡𝜎𝑡=𝑃𝑎𝑑2𝛿Ly(m)0不需要校验过渡段长度，直管段中可以有锚固段存在管道过渡段伸长量计算𝐿=𝛼𝐸𝑡1−𝑡0−𝜈𝜎𝑡𝐴×106𝑓∆𝐿=𝛼𝑡1−𝑡0−𝑓𝐿2𝐸𝐴×106𝐿−𝐿𝑦2𝐿≥2.3𝐷𝐶4𝐸𝐼×1060.25𝑁𝑎=𝛼𝐸𝑡1−𝑡0−𝜈𝜎𝑡𝐴×106𝜎𝑃=1−𝜈𝜎𝑡−𝛼𝐸𝑡1−𝑡0≤3𝜎𝐿≤3𝜎−𝜎𝑡1.6𝐹𝐴×106DND(mm)d(mm)F(kN)Lf(m)f(kN/m)25.0033.702.6036.4428.301.2932.0042.402.6046.6329.181.6040.0048.302.6053.5533.511.6050.0060.003.5089.1242.842.0870.0076.004.00129.7962.402.0880.0089.004.00153.2263.502.41100.00114.004.00198.2963.863.11125.00140.004.50274.7977.303.56150.00159.004.50313.3277.944.02200.00219.006.00575.93108.835.29250.00273.006.00721.93113.986.33300.00325.007.001003.15132.967.55350.00377.007.001167.19123.839.43400.00426.007.001321.77123.8410.67500.00529.008.001878.32139.4013.47600.00639.009.002518.70151.4716.52最大允许摩擦长度计算结果实例