13208.9kPakPap100kPaq50,yxzxytg2)(3'分别代表三个方向上的主应力,以σ1=σz,σx=σy=σ3为0,计算完成下表。zyx,,zxyyxzxytg2)(3'ˊ=60zxy关于的解释2222(1)31()()1()1(2)(3)1(4)331(5)3(6)(7)yxzxzxyxzxxxzxyxbbctgzyqbbbbzqzbbybzpzybpzzybb0计算公式的推导221000028194%0.0046100,1000080.01,2.3tvvtUectTHnteth567天,U=94%;n=100,U=99%-时间?已知砂土试样的1=800kPa,2=500kPa,3=200kPa,计算I1、I2、I3、J2、J3、p、q和各是多少;如果1=800kPa,2=3=200kPa,上述各值为多少?123800,500,200kPakPakPa123800,200,200kPakPakPa131()dd131tddEd1123()tttddddEE313131[()1(12)iittddduduBdAddddEdA•不排水试验0.33,/zxk0.1kxz=qφ’=32.1;φcu=11.9313[()]uBACTCRTC13/41210,ckPaRTC答案:φ’=20;φcu=13G=2.67e=0.892m答案H=2m0.54t/m2H=2m2t/m2H=2m3.76t/m21.76t/m2H=2m2t/m2H=1.69m0.44t/m2H=0.31mz19151896.5170.0225.14m1m4m1m10(m)扬压力(t/m2)7.54.74.33.83.32.320304050,78.48kPa8820.36kPa答案111.84kPa10.8m6m51.21kPa9m1.8m21.18kPa12.83kPa105.95kPa6m答案0370c,,;318.7/satKNmi=9/12水头损失各4.5m90kPa105kPa()()aazappzppKKjzpKKjz49.92kPa56.07kPa6m6m111.84kPa9.89m62.63kPa0.91m0kPa10.8m答案(a)3.5m57.11kPa2.81m0kPa3.5m2.5m1.99m27.85kPa11.37kPa0kPa0kPa21.29kPa23.25kPa17.66kPa1.8m2.5m3m88.04kPa17m5m72.65kPaθ=36.50505028.2rm220001.366lglg(10.2)HhQkRrhlHhrlr237.15kPa11.97m3.03m90kPa9m6m147.15kPa15m0120020.80.711.22000iqBScmE查表得μ0=0.8,μ1=0.70,Si=0.112m(未修正),ⅠⅡⅡⅠ讨论:从图可见:如果粘土在上部,它阻挡了第二层土的排水路线,可以近似用8m厚的Ⅰ层土计算;如果粘性土在下部,它实际上成为不排水层,可以近似用6m后的第Ⅱ层土计算。所以上述近似计算方法不合理。