《钢筋混凝土结构》部分相关公式

附录：相关公式及表格一、混凝土基本构件承载力计算部分公式1．受弯构件正截面承载力(单筋矩形截面)1fcbx=fyAsMu=1fcbx(h0–x/2)=αs1fcbh02=fyAs(h0–x/2)γs=0.5(1+sa21)ξ=1-sa212．受弯构件斜截面承载力Vu=0.7ftbh0+1.5fyv(Asv/S)h0+0.8fyAsbsin000.1175.1hfsAbhfVyvsvtu+0.8fyAsbsinΦ6-(As=28.3mm2),Φ8-(As=50.3mm2)3.受压构件正截面承载力（对称配筋）η=1+014001hei(hl0)2•1•21=NAfc5.02=1.15-0.010l/h(1)大偏压As=As=)()2(001SycahfxhbxfNe或As=As=)(0SyahfeN(2)小偏压ξ=002008.045.0bhfahbhfNebhfNcmbcmcmb+ξbAs=As=)()5.01(020SycmahfbhfNe二、砌体轴心受压构件承载力计算公式fANu附表1：受压砌体承载力影响系数βhe/或the/00.100.150.1750.2250.25310.890.790.730.620.5780.890.670.570.520.440.40100.830.610.520.470.400.37120.780.560.470.430.370.34