写出下列幂的运算公式的逆向形式,完成后面的题目.=+nma=−nma=mna=nnba同底数幂的乘法一、填空题1.同底数幂相乘,底数,。2.a(____)·a4=a20.(在括号内填数)3.若102·10m=102003,则m=.4.23·83=2n,则n=.5.-a3·(-a)5=;x·x2·x3y=.6.a5·an+a3·a2+n–a·a4+n+a2·a3+n=.7.a-b)3·(a-b)5=;(x+y)·(x+y)4=.8.111010mn+−×=________,456(6)−×−=______.9.234xxxx+=________,25()()xyxy++=_________________.10.31010010100100100100001010××+××−××=___________.11.若34maaa=,则m=________;若416axxx=,则a=__________;12.若2,5mnaa==,则mna+=________.二、选择题1.下面计算正确的是()A.326bbb=;B.336xxx+=;C.426aaa+=;D.56mmm=2.81×27可记为()A.39B.73C.63D.1234.下列各式正确的是()A.3a2·5a3=15a6B.-3x4·(-2x2)=-6x6C.3x3·2x4=6x12D.(-b)3·(-b)5=b85.设am=8,an=16,则anm+=()A.24B.32C.64D.1286.若am=2,an=3,则am+n=().A.5B.6C.8D.97.下列计算题正确的是()A.am·a2=a2mB.x3·x2·x=x5C.x4·x4=2x4D.ya+1·ya-1=y2a8.在等式a3·a2()=a11中,括号里面的代数式应当是().A.a7B.a8C.a6D.a59.x3m+3可写成().A.3xm+1B.x3m+x3C.x3·xm+1D.x3m·x3二、计算题(1)23()()()ababab−⋅−⋅−(2)23324()2()xxxxxx−⋅+⋅−−⋅(4)122333mmmxxxxxx−−−⋅+⋅−⋅⋅(5)(2x-y)3·(2x-y)·(2x-y)4;三、简答题1、62(0,1)xxppppp⋅=≠≠,求x2.已知xn-3·xn+3=x10,求n的值.3.已知2m=4,2n=16.求2m+n的值.4..若10,8abxx==,求abx+同底数幂的除法1.计算(1)26aa÷(2))()(8bb−÷−(3)24)()(abab÷(4)232ttm÷+(m是正整数)(5)()85aa=⋅(6)()62mm=⋅(7)()1032xxx=⋅⋅(8)()73)()bb−=⋅−((9)()63)()(yxyx−=⋅−(10)()8224=⋅2.下面的计算是否正确?如有错误,请改正.(1)248aaa=÷(2)ttt=÷910(3)55mmm=÷(4)426)()(zzz−=−÷−3.计算:(1)131533÷(2)473434)()(−÷−(3))()(5aa−÷−(4)25)()(xyxy−÷−(5)25)aa÷−((6)57xx÷(7)35)()(xyxy÷(8)453ppp÷⋅(9))()()(46xxx−÷−÷−(10)[]3512)(xxx⋅−÷(11)xxxxx⋅÷⋅÷431012(12)32673)()(xxx÷4、简答题(1)已知4,32==baxx,求bax−.(2)已知3,5==nmxx,求nmx32−.(3)已知3,2==yxaa,求yxa−,yxa−2,yxa32−的值.幂的乘方与积的乘方一、填空题1.221()3abc−=________,23()naa⋅=_________.2.5237()()pqpq⎡⎤⎡⎤+⋅+⎣⎦⎣⎦=_________,23()4nnnnab=.3.3()214()aaa⋅=.4.23222(3)()aaa+⋅=__________.5.221()()nnxyxy−⋅=__________.6.1001001()(3)3×−=_________,220042003{[(1)]}−−−=_____.7.若2,3nnxy==,则()nxy=_______,23()nxy=________.8.若4312882n×=,则n=__________.二、选择题9.若a为有理数,则32()a的值为()A.有理数B.正数C.零或负数D.正数或零10.若33()0ab,则a与b的关系是()A.异号B.同号C.都不为零D.关系不确定11.计算82332()()[()]ppp−⋅−⋅−的结果是()A.-20pB.20pC.-18pD.18p12.44xy×=()A.16xyB.4xyC.16xy+D.2()2xy+13.下列命题中,正确的有()①33()mnmnxx+++=,②m为正奇数时,一定有等式(4)4mm−=−成立,③等式(2)2mm−=,无论m为何值时都不成立④三个等式:236326236(),(),[()]aaaaaa−=−=−−=都不成立()A.1个B.2个C.3个D.4个14.已知│x│=1,│y│=12,则20332()xxy−的值等于()A.-34或-54B.34或54C.34D.-5415.已知5544332,3,4abc===,则a、b、c的大小关系是()A.bcaB.abcC.cabD.abc三、解答题17.计算4224223322()()()()()()xxxxxxxx+−⋅−−⋅−⋅−;18.已知105,106ab==,求(1)231010ab+的值;(2)2310ab+的值(7分)19.已知333,2mnab==,求233242()()mnmnmnababab+−⋅⋅⋅的值(7分)