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1InstructionofAnsystemperaturefieldcalculationQuestion1:Consideraninfinite(inonedirection)platewithinitialtemperatureT0.OneendoftheplateisexposedtotheenvironmentofwhichthetemperatureisTe(IIItypeboundarycondition).Analyzethetemperaturedistributionintheplateduringtheperiodof2000s.问题1：考虑一个方向无限长的平板，初始温度为T0，一段暴露在温度为Te的环境中，分析其在2000s内温度分布情况。Basicparameters基本物性参数Geometry几何：a=1m,b=0.1mMaterial材料：λ=54W/m·oC,ρ=7800kg/m3,cp=465J/kg·oCLoads载荷：T0=0oC,Te=1000oC,h=50W/m2·oCJobnameanddirectorysettings设置文件名、存储路径Menu|File|ChangeJobnameMenu|File|ChangeDirectoryPreprocessing前处理(1)DefineElementType定义单元类型Preprocessor|ElementType|Add/Edit/DeleteAdd:ThermalMass|Solid|Quad4node55(2)SetMaterialProperties设置材料属性Preprocessor|MaterialProps|MaterialModelsThermal:Conductivity:IsotropicKXX=54Thermal:Density=7800Thermal:SpecificHeat=4652Modeling建模(1)CreateNode1建立节点1Preprocessor|Modeling|Create|Nodes|InActiveCSNo.:1,(x,y,z)=(0,0,0)(2)CreateNode12建立节点12Preprocessor|Modeling|Create|Nodes|InActiveCSNo.:2,(x,y,z)=(0,1,0)(3)FillBetweenNode1and12在节点1，12间填充其余节点Preprocessor|Modeling|Create|Nodes|FillBetweenNdsNumberofnodestofill:10Spacingratio:1(均匀网格)(4)CreateNode13~24bycopying复制生成节点13～24Preprocessor|Modeling|Copy|Nodes|CopyPickAll选择所有节点Totalnumberofcopies:2复制2份（包含原先的1份）X-offset:0.1设置X方向偏移量(5)CreateElement1生成单元1Preprocessor|Modeling|Create|Elements|AutoNumbered|ThruNodesSelect1,13,14,2(withmouse)(6)CopyElement2~10bycopying复制生成其余单元Preprocessor|Modeling|Copy|Elements|AutoNumberedPickAll选择所有单元Totalnumberofcopies:11复制11份（包含原先的1份）Nodenumberincrement:1设置节点增量ApplyingLoads加载（设置边界条件和初始条件）(1)ApplyconventionloadsonNode12and24在节点12，24上加对流载荷Preprocessor|Loads|DefineLoads|Apply|Thermal|Convection|OnNodesPick12,24VALIFilmcoefficient:50换热系数VAL2LBulktemperature:1000环境温度(2)Setinitialtemperature(uniformtemperature)设置初始条件（均匀温度）Solution|DefineLoads|Settings|UniformTempUniformTemperature:0Solution求解(1)SetAnalysisTypeasTransient设置分析类型为瞬态分析Solution|AnalysisType|NewAnalysisTransient3(2)Setsolutioncontrols设置分析控制参数Solution|AnalysisType|Sol’nControls”Transient”Label:SteppedLoading”Basic”Label:Timeatendofloadstep:10000;Automatictimestepping:on;Timeincrement:10;Frequency:Writeeverysubstep(3)Solve求解Solution|Solve|CurrentLSViewingResults查看结果(1)TimeHistPostpro时间历程后处理器Adddata添加数据:TimeHistPostpro|Adddata:NodalSolution:DOFSolution:NodalTemperature:VariableName:T1;Node1VariableName:T5;Node5VariableName:T9;Node9VariableName:T11;Node11(2)List/Graph列表/作图Selectthevariables选择变量:Listdata/Graphdata(3)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas(4)GeneralPostpro通用后处理器Selectthedataofcertaintime选择某一时刻的数据:GeneralPostpro|ReadResults|BypickPlotthecontourmapoftemperaturedistribution绘制该时刻温度分布等值线图:GeneralPostpro|PlotResults|ContourPlot|NodalSolu|NodalSolution:DOFSolution:Temperature(5)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas(6)Animate生成动画Menu|PlotCtrls|Animate|OverTimeNumberofanimationframes:100Question2:ConsiderasolidcylinderwithinitialtemperatureT0.ThetopsurfaceofthecylinderisexposedtotheenvironmentofwhichthetemperatureisTe(IIItypeboundarycondition)andtheothersurfacesareheatinsulation(IItypeboundarycondition).Analyzethetemperaturedistributioninthecylinderduringtheperiodof1000s.问题2：考虑一个初始温度为T0的圆柱体，一段暴露在温度为Te的环境中，其余界面视为绝热，分析其在1000s内温度分布情况。4Basicparameters基本物性参数Geometry几何：r=0.025m,h=0.05mMaterial材料：λ=25W/m·oC,ρ=7800kg/m3,cp=500J/kg·oCLoads载荷：T0=25oC,Te=100oC,h=100W/m2·oCJobnameanddirectorysettings设置文件名、存储路径Menu|File|ChangeJobnameMenu|File|ChangeDirectoryPreprocessing前处理(1)DefineElementType定义单元类型Preprocessor|ElementType|Add/Edit/DeleteThermalMass:Solid:Brick8node70(2)SetMaterialProperties设置材料属性Preprocessor|MaterialProps|MaterialModelsThermal:Conductivity:IsotropicKXX=25Thermal:Density=7800Thermal:SpecificHeat=500Modeling建模(1)Createthecylindermodel建立圆柱体模型Preprocessor|Modeling|Create|Volumes|Cylinder|SolidCylinderWPX:0WPY:0Radius:0.025Depth:0.05(2)Adjusttheview调整视图RightToolbar|IsometricView(3)Mesh划分网格Preprocessor|Meshing|MeshToolSmartSize(optional):Mesh:selectthecylinder选择圆柱体5ApplyingLoads加载(1)Applyconventionloadsonthetop在上表面加对流载荷Preprocessor|Loads|DefineLoads|Apply|Thermal|Convection|OnAreasPickthetopsurfacebymouse选择上表面(用鼠标)VALIFilmcoefficient:100换热系数VAL2LBulktemperature:100环境温度(2)Setinitialtemperature(uniformtemperature)设置初始条件（均匀温度）Solution|DefineLoads|Settings|UniformTempUniformTemperature:25Solution求解(1)SetAnalysisTypeasTransient设置分析类型为瞬态分析Solution|AnalysisType|NewAnalysisTransient(2)Setsolutioncontrols设置分析控制参数Solution|AnalysisType|Sol’nControls”Transient”Label:SteppedLoading”Basic”Label:Timeatendofloadstep:1000;Automatictimestepping:on;Timeincrement:10;Frequency:Writeeverysubstep(3)Solve求解Solution|Solve|CurrentLSViewingResults查看结果(1)GeneralPostpro通用后处理器Selectthedataofcertaintime选择某一时刻的数据:GeneralPostpro|ReadResults|BypickPlotthecontourmapoftemperaturedistribution绘制该时刻温度分布等值线图:GeneralPostpro|PlotResults|ContourPlot|NodalSolu|NodalSolution:DOFSolution:Temperature(2)Saveimage保存图片Menu|PlotCtrls|CaptureImage:File|Saveas(3)Animate生成动画Menu|PlotCtrls|Animate|OverTimeNumberofanimationframes: