结构力学-第五章-作业参考答案(整理-BY-TANG-Gui-he)

12005TANGGui-he5152MH=0Fay=75kN.FY=0Fhy=45kNAFNAB=-100kN.FNAC=125kN.CFNBC=-50,FNCE=103.1kN.BDEGFCollegeofwaterconservancyandCivilEngineering,SCAU2535435556IIIIII(1)IIMCollegeofwaterconservancyandCivilEngineering,SCAU45712Ma=0Mb=0Fa=Fb=7/2F31-1Md=0,FN12d+Fa4d-F(d+2d+3d)=0FN1=-4F()42-2CE=2dsin450=1.414d,Mc=0FN12d-Fa2d-FN21.414d+Fd=0,FN2=1.414F()52-2Md=0FN12d-Fa4d-FN31.414d+FFN1(2d+3d)=0,Fn3=-.702F()6FFy=0,FN4=-1.414Fsin450=-F()5851NaF06/1330DNaMFdFd=×+×=∑6/1330NaFdFd×+×=13/2NaFF=-⇒2NbFC22NbNayFFF=-=591-1,Fx=0FNbFN510517CollegeofwaterconservancyandCivilEngineering,SCAU6519()()()()()()()06060I060.70.510.6301500.7Dcos0154.033sin0350.51A612cosAxAyBAyDEDEDEADADADDFDFADFFkNFkNMCFmFmmkNmmmFkNFFaFFaFFkNFa==↑=↑=×-×+-××=⇒=⇒-=⇒=+=⇒=-=+∑()()()()()()()()()()22cos0150.52150150.5235154.030.51sin3cos10/37.5.220.51sincos.10162ACACDEACBCDFEGADBEAyADADAyADADFbFFkNFFkNFFkNFFkNMFFFamFakNmmkNmxMxFFaxFax=⇒=-===-==-===-×-×-××=-=---×=()()()()()()222.55`12.510.0.51sincos.10347.5106247.510SAyADADDFSxxFxMxxxMxFFaxFaxFxxFxx-==-=---×+-=-=-7Continued