絮凝池设计(作业)

整理文档很辛苦,赏杯茶钱您下走!

免费阅读已结束,点击下载阅读编辑剩下 ...

阅读已结束,您可以下载文档离线阅读编辑

资源描述

设计某水厂的絮凝池,已知水量Q=70000m3/d=2917m3/h1、用往复式隔板絮凝池2、选用数据:(1)廊道内流速采用六档:v1=o.5m/s,v2=o.4m/s,v3=0.35m/s,v4=o.3m/s,v5=o.25m/sv6=o.2m/s.(2)絮凝时间:T=20min(3)池内平均水深:H1=2m(4)超高:H2=0.3m(5)池数:n=2个3、计算总容积W=QT/60=2917×20/60=972m3F’=W/(n×H1)=972/(2×2)=243m2设池子宽度:B=20m池子长度:L’=243/20=12.15m隔板间距按廊道流速不同分成六档:a1=Q/(3600×n×V1×H1)=2917/(3600×2×0.5×2)=0.405m取a1=0.405m则实际流速:V’1=0.46m/s取a2=0.65则实际流速:V’2=0.42m/s按上法计算得:a3=0.75m,V’3=0.37m/sa4=0.9m,V’4=0.3m/sa5=1.1m,V’5=0.25m/sa6=1.35m,V’6=0.2m/s每一种间隔采取3条,则廊道总数为18条,水流转弯次数为17次,则池子长度L’=3(a1+a2+a3+a4+a5+a6)=3(0.6+0.65+0.75+0.9+1.1+1.35)=16.05m隔板厚按0.2m计,则池子总长L=16.05+0.2×(18-1)=19.45m按廊道内的不同流速分成六段,分别计算水头损失:第一段:水力半径R1=a1×H1/(a1+2H1)=0.6×2/(0.6+2×2)=0.26m槽壁粗糙系数n=0.013流速系数Cn=1/n×Rny1Y1=0.149故C1=Rny1/n=62.9第一段廊道长度:l1=3B=3×20=60m第一段水流转弯次数S2=3则絮凝池第一段水头损失为h1=0.073miiiiitilRCvgvmh22212各段水头损失计算结果段数MiIiRiV0viciCi2hi13600.260.400.4762.93956.410.07323600.300.3840.4264.14108.810.06733600.330.320.3765.24251.040.04743600.400.252O.367.34529.290.02953600.440.2170.2568.24651.240.02162400.530.1870.270.14914.010.016H总=0.253m求得G=45sGT值计算取T为20minGT=45×20×60=54000在104到105之内池底坡度I=h/L=0.253/20=1.26%

1 / 3
下载文档,编辑使用

©2015-2020 m.777doc.com 三七文档.

备案号:鲁ICP备2024069028号-1 客服联系 QQ:2149211541

×
保存成功