110kV电网继电保护配置与线路保护整定计算(计算书)

第一章电力系统各元件主要参数的计算1.1基准值选择基准功率：SB=100MV·A基准电压：UB=115V基准电流：AUSIBBB5023基准电抗：25.1322BBBSUZ1.2发电机参数的计算有限容量发电机的电抗标幺值计算公式：NBdGSSXX*对于无穷大容量系统的电抗标幺值计算公式：SSXBS*式中：''dX——发电机次暂态电抗BS——基准容量100MVANS——发电机额定容量MVAS——系统出口母线三相短路容量，取800MVA利用以上公式对100MW的发电机:已知：MWAPN100取8.0cos则MVAPSNN1258.0100cos088.012510011.0*NBdGSSXX638.1125.132088.0*BGGZXX对于无穷大容量电源S：最大运行方式下正序阻抗16.2125.13216.0*BSSZXX最大运行方式下零序阻抗48.6325.13248.0*00BSSZXX最小运行方式下正序阻抗385.3425.13226.0*BSSZXX最小运行方式下零序阻抗155.10325.13278.0*BSSZXX1.3变压器参数的计算变压器电抗标幺值计算公式：NBKTSSUX100(%)*式中：(%)KU——变压器短路电压百分值BS——基准容量100MVANS——变压器额定容量MVA(1)利用以上公式对T(T1,T2,T3):已知:MVASN1505.12(%)KU则083.01501001005.12100(%)*NBKTSSUX977.1025.132083.0*BTTZXX(2)对T4(T5):已知:MVASN5012(%)KU则24.05010010012100(%)*4NBKTSSUX74.3125.13224.0*44BTTZXX(3)对T6(T7):已知:MVASN5.315.10(%)KU则333.05.311001005.10100(%)*6NBKTSSUX083.4025.132333.0*66BTTZXX1.4输电线路参数的计算输电线路电阻忽略不计，设线路正序阻抗为0.4/KM，线路零序阻抗为1.21/KM线路阻抗有名值的计算：正序阻抗1XXl零序阻抗0XXl线路阻抗标幺值的计算：正序阻抗21*1BBUlSXX零序阻抗20*0BBUlSXX式中：1X------------每公里线路正序阻抗值Ω/KM0X-----------每公里线路零序阻抗值Ω/KMl------------线路长度KMBU-------------------基准电压115KVBS-------------------基准容量100MVA(1)线路正序阻抗:2.5134.01ABABlXX039.0115100134.0221*BBABABUSlXX2.9234.01BCBClXX070.0115100234.0221*BBBCBCUSlXX8.4124.01CACAlXX036.0115100124.0221*BBCACAUSlXX22554.01SCSClXX166.0115100554.0221*BBSCSCUSlXX(2)线路零序电抗:73.151321.100ABABlXX119.01151001321.1220*0BBABABUSlXX83.272321.100BCBClXX21.01151002321.1220*0BBBCBCUSlXX52.141221.100CACAlXX110.01151001221.1220*0BBCACAUSlXX55.665521.100SCSClXX503.01151005521.1220*0BBSCSCUSlXX第二章短路电流的计算2.1线路AC上零序电流的计算2.1.1线路AC末端发生短路时零序电流计算B母线发生最大接地电流时，C1，C2接通，B、C母线连通。)||)((||)(1ACBCABTGSCSXXXXXXXZ)8.4||)2.92.5(977.10638.11(||)166.016.21()(8.11))(||)((||000500700COAOTTBOTXXXXXXZ)(9.352.1483.2773.1552.1473.15000000CABCABACABAOXXXXXX)(5.752.1483.2773.1583.2773.15000000CABCABBCBABOXXXXXX)(0.752.1483.2773.1583.2752.14000000CABCABCBCACOXXXXXX)0.7)9.3977.10(||)74.315.7((||083.400Z)(3.12ABC1C2S图正序等值图ABC图零序等值图ABCO图经零序等值图又因为10XX,所以取单相接地短路的零序电流进行整定。)(850.13.128.1123/11520110kAZZEIf在零序网中，按照零序导纳分配零序电流求取流经保护1的零序电流T7BCACCBABTT5I将其T7BCACCBIOQ)(0.374.31977.1073.15977.1073.155000000TTABTABAOXXXXXX)(5.874.31977.1073.1574.3173.1550005000TTABTABCOXXXXXX)(0.674.31977.1073.15977.1074.3150000500TTABTTQOXXXXXXCOBCAOACCOBCQOCOBCAOACTTfZZZZZZZZZZZZZII0000000000070700)1(max10)(||)(5.883.27352.145.883.276)5.883.27(||)352.14(083.40083.40850.1)(864.0kA2.1.2距线路AC首端15%处短路时最小零序电流的计算最小短路电流时，BC母线分列运行)15.0(||)85.0(761ACTGACTTSCSXXXXXXXXZ)8.415.0977.10638.11(||)8.485.02083.40166.0385.34()(89.22)85.0(||)15.0(700000TACACTXXXXZ)83.4052.1485.0(||)52.1415.0977.10()(55.10因为01XX,所以取单相接地短路的零序电流进行校验)(179.155.1089.2223/11520110kAZZEIf同理，按照零序导纳分配零序电流，求取流经保护1的零序电流70007000)1(min1085.0TACTTACfXXXXXII083.4052.14977.10083.4052.1485.0179.1)(04.1kAAC2SC1图正序网络CA图零序等值图2.2线路AC末端三相短路的最大短路电流计算考虑BC母线并列运行，B母线发生三相短路的情况))(||(||)(1BCABACTGSCSXXXXXXXZ))2.92.5(||8.4977.10638.11(||)166.016.21()(75.11ABC图正序等值图在正序网中，按照导纳分配短路电流求取流经保护1的最大短路电流)(65.575.113/115max,)3(kAIdACBCABTGSCSSCSddXXXXXXXXXII||)(max,)3(max,1)3(CABCABBCABXXXXX8.4||)2.92.5(977.10638.11166.016.21166.016.2165.58.42.92.52.92.5)(9.1kA2.3线路AC下级线路最小零序电流计算2.3.1乙变电所低压母线端发生短路BC母线并列，系统闭环运行，C母线分段运行)||)((||)(71ACBCABTGTSCSXXXXXXXXZ)8.4||)2.92.5(977.10638.11(||)083.40166.0385.34()(4.19ABC2SC1图正序等值图0Z，无零序电流流过，此段线路不做配合。2.3.2甲变电所高压侧B母线端发生短路)||)((||)(71ACBCABTGTSCSXXXXXXXXZ)(3.18.42.92.58.42.5BCACABACABAOXXXXXX)(3.28.42.92.52.98.4BCACABBCACCOXXXXXX)(5.28.42.92.52.92.5BCACABBCABBOXXXXXX)(||)(671AOTGCOTTSCSBOXXXXXXXXXZ)3.1977.10638.11(||)2083.40166.0385.34(5.2)(3.22))(||(||0000500TBCACABTXXXXXZ)977.10)83.2752.14(||73.15(||74.31)(1.13因为01XX,所以取单相接地短路的零序电流进行校验)(151.11.133.2223/11520110kAZZEIf在零序网中，按照零序导纳分配零序电流求取流经保护1的零序电流ACBCABABTACBCABTTfZZZZZZZZZZII0000000050500)1(min10)(||977.10)52.1483.27(||73.1574.3174.31151.152.1483.2773.1573.15)(183.0kAABC2SC1图正序等值图将其ABC2SC1O图正序等值图ABC图零序等值图2.3.3S母线发生短路)||)((||671ACBCABTGTTSCSXXXXXXXXXZ)8.4||)2.92.5(977.10531.162083.40166.0(||385.34)(3.26)(6.106083.4055.667000TSCXXZ因为10XX,所以取两相接地短路的零序电流进行校验ABC1C2S图正序等值图)(277.06.10623.263/11520110kAZZEIf因为保护1无零序电流流过，此段线路不做配合。2.4乙变电所低压母线端最大三相短路电流761||)(||)(TTACTGSCSXXXXXXXZ083.40||083.40)8.4977.10638.11(||)166.016.21()(32)(2323/11531)3(max,kAZEIkABC1C2S图正序等值图2.5A母线最大短路零序电流)(||)(1ACSCSTGXXXXXZ)8.4166.016.21(||)977.10638.11()(1.12))(||)((||007005000AOCOTBOTTXXXXXXZ)(9.352.1483.2773.1552.1473.15000000CABCABACABAOXXXXXX)(5.752.1483.2773.1583.2773.15000000CABCABBCBABOXXXXXX)(0.752.1483.2773.1583.2752.14000000