船舶课程设计

鲁东大学交通学院浮体静力学课程设计实验报告姓名翟敏学号20102814137班级船舶1001指导教师胡丽芬日期2012-12-25成绩一邦容曲线计算及绘制1.要求计算以下各站处的横剖面面积及面积矩曲线，并绘出邦戎曲线图。0站，1站，2站，3站，4站，5站，6站，7站，8站，9站，10站注：假设甲板为平甲板已知船型：油船主尺度：船长89.00m,型宽14.60m,型深7.00m,设计吃水5.50m型值表见附录1（提供电子版资料）2.计算（采用梯形法计算）横剖面面积'220dAydzdysi式中：'''012012innyyyyyyy…横剖面面积As对基线Oy轴的静矩111022niiiioyiiiyyzzMzzz式中)nyy'(ny...yy'yΣ'knniii00021103.列表.画图横剖面面积As横剖面面积As对基线Oy轴的静矩Moy水线0.0000.2500.5000.75012345670站0.0000.0000.0000.0000.0000.0000.0000.0001.3465.96113.4531站0.0000.3520.8121.3702.0165.41410.14216.40824.72535.25547.4122站0.0001.1292.6494.4136.36915.57226.54538.80552.00065.84980.1333站0.0002.2114.8557.75010.81624.01638.12552.58867.16881.76896.3684站0.0003.0726.3989.87413.43627.92342.52357.12371.72386.323100.9235站0.0003.1916.59310.12513.72728.28342.88357.48372.08386.683101.2836站0.0003.1916.59310.12513.72728.28342.88357.48372.08386.683101.2837站0.0002.9966.2969.74813.28427.70942.30156.90171.50186.101100.7018站0.0002.0224.5127.22410.08022.28435.29948.74962.50276.53590.8299站0.0000.6911.6832.8484.13710.02916.72123.88131.53339.94749.41110站0.0000.0290.1120.2440.4241.5433.2025.2276.7947.4148.194水线0.000.250.500.7512345670站0.0000.0000.0000.0000.0000.0000.0000.00013.46052.688111.8101站0.0000.0260.0890.2030.37514.07430.33458.782106.392175.620265.0522站0.0000.0860.2940.6441.15538.94674.082125.314193.224277.920379.0843站0.0000.1560.5051.0671.85157.319100.417158.657231.657319.257421.4574站0.0000.2020.6301.2912.19064.238108.038166.438239.438327.038429.2385站0.0000.2070.6431.3142.22164.734108.534166.934239.934327.534429.7346站0.0000.2070.6431.3142.22164.734108.534166.934239.934327.534429.7347站0.0000.2000.6251.2822.17463.948107.748166.148239.148326.748428.9488站0.0000.1470.4761.0001.72953.15093.008147.464216.924301.968402.8669站0.0000.0560.1930.4240.76024.98945.88775.303115.053168.321238.67110站0.0000.0040.0170.0470.0974.41210.07618.72423.58425.19234.236012345678910邦戎曲线As=f(z)Moy=f(z)二静水力曲线计算与绘制1.要求计算各吃水处的以下各要素，并绘出静水力曲线图。(1)线面面积Aw⑵漂心纵向坐标Xf⑶每厘米吃水吨数TPC⑷水线面系数⑸排水体积V⑹排水量W(附体系数取1.006)⑺浮心纵向坐标⑻浮心垂向坐标⑼横稳心垂向坐标⑽纵稳心垂向坐标⑾每厘米纵倾力矩曲线⑿方形系数计算以下各吃水：1m,2m,3m,4m,5m,6m2.计算(1)水线面面积计算原理20222lnlilAwydxyin其中012nyy（2）漂心纵向坐标2'2'22LLiioyFLwiLxydxkyMxLAyydz（3）每厘米吃水吨数（ω=1.025tf/m)（4）水线面系数LBAwCwp（5）排水体积20022LddLwAdzydxdz（6）排水量kkω=1.025tf/mK=1.006(7)浮心纵向坐标00iidFwyOzBdwxAdzMxAdz100wATPC（8）浮心垂向坐标00iidWxOyBdwzAdzMzAdz（9）横稳心垂向坐标MBzMKMBBKMBz(10）纵稳心垂向坐标MLLLLBzMKMBBKMBz222222LLwFLwFLFLxydxAxIAxIMB(11）每厘米纵倾力矩曲线100100LLGMBMMTCLL222222LLFWFWLLFLxAydxxxAIIBM（12）方形系数BCLBd3.所得值如下表，图如下水线0m1m2m3m4m5m6mAw638.842970.5811074.4701141.4071204.1431351.1271487.448Xf2.7393.9473.7063.1672.1492.2294.727TPC9.94811.01311.69912.34213.84915.246Cwp0.7470.8270.8780.9271.0401.145V804.7111827.2372935.1764107.9515385.5866804.873W829.7781884.1553026.6064235.9135553.3477016.845Xb4.5554.1443.8743.5233.2073.276Zb0.6031.1191.6462.1792.7373.318Zm15.6708.7286.7356.0325.9486.211Zml558.442307.241220.195179.022178.672169.320MTC52.00964.80774.32284.168109.779130.877CB0.1130.2560.4110.5750.7540.952三．装载稳性计算要求：计算载况：满载出港(重量W=5519.52t，重心Xg=-0.85m,Zg=5.02m)计算内容：浮态及初稳性静稳性曲线及动稳性曲线稳性校核（注：自由液面修正及进水角暂不考虑）已知：受风面积=360m^2受风面积形心距水线高=3.65m稳性插值曲线航区：近海1.计算浮态和稳性已知重量W=5519.52t,则排水量为5519.52t.。利用静水力曲线图，如下主要尺度：船长L(m)89.000型宽B(m)14.600型深D(m)7.000吃水d(m)5.500可求出浮态和稳性，如下表：项目单位符号及公式满载出港排水量tΔ5519.52平均吃水md4.976重心纵向坐标mXg-0.85浮心纵向坐标mXb3.21重心竖向坐标mZg5.02纵稳心距基线高mZml238.23纵向初稳心高m233.21每厘米纵倾力矩t·m144.63漂心纵向坐标mXf-2.21纵倾力臂mXg-Xb-4.06纵倾力矩t·m-22409.25纵倾值m-1.55首吃水增量m-0.81尾吃水增量m0.74首吃水m4.16尾吃水mddddA5.71横稳心距基线高mZm5.95初稳心高m0.932.(1)静稳性曲线由已给出的稳性横截曲线图，可求得Ls与V的关系，由公式sinGszll可计算各倾角下的复原力臂l，并绘制该排水量下的静稳性曲线fl。(2)动稳性曲线动稳性曲线是静稳性曲线的积分曲线，由公式0ldld可求得fld的关系，绘制动稳性曲线。（3）列表及绘图角度lsLLd50.5310.0940.004101.0650.1940.016151.6040.3050.038202.1150.3990.067252.6080.4860.103303.1020.5920.144353.5740.6940.192403.9890.7620.242504.5670.7220.334604.8920.5440.397705.0150.2980.428804.9520.0090.435904.741-0.2790.4333.稳性校核a.稳性衡准数K是对船舶稳性的重要基本要求之一。规则规定：船舶在所核算的各种装载情况下的稳性，应符合1fqllK（1）风倾力臂fl(m)可按下式求得9810ZpAlff求得00419.0flm(2)最小倾覆力臂ql是根据静稳性曲线或动稳性曲线以及横摇角0来确定的。3241028.15CCCC式中：4.3.2.1CCCC为系数。经过计算可得1013.068.0235.04321CCCC确定96.250通过动稳性曲线可确定ql1928.0ql求出1K，符合要求b.初稳性高和静稳性曲线船舶在各种装载情况下初稳性高和静稳性曲线满足下列要求：（1）初稳性高为0.93m大于0.15m。（2）横倾角30时的复原力臂为0.592m大于0.2m。（3）船舶最大复原力臂所对应的横倾角为5.41大于30。