退出下一页上一页章目录总目录制作群主页一、图示电路,已知U=100V,I=I1=I2,且电路消耗的功率为866W,试求R、XL、XC。解:V0100U令A1030cos100866cos21UPIII101010011IUCXC5j3530100100j2IUXRLCXjLXjRI1I2IU+-1I2II1IU3030235R5LX退出下一页上一页章目录总目录制作群主页解:⑴A90230j22UI二、图示电路,已知电流表读数为1.5A,求:⑴、、、;⑵电源供给的视在功率、有功功率和无功功率。I1U2U3U1I+-Aj30Ω0Ω42I1U2U3U+-+-j50Ω4Ω2j18Ω+-UIA05.11I令A1.535.221IIIV0604012IUV75j18j241IUV9.3612550j3IU⑵V01609.361256075j321UUUUAV4005.2160UISW2401.53cos400cosSPvar3201.53sin400sinSQ退出下一页上一页章目录总目录制作群主页解:三、图示电路,试求负载ZL为何值时可获最大功率?最大功率为多少?025.02j022j111UUn0211nUU1oc022jnUUV6.2620ocU解得1oo2jUIU1o15.02jUIU1j1ooeqIUZ解得有时,当1j1*eqLZZeq2ocmax4RUPW514202退出下一页上一页章目录总目录制作群主页解:四、已知:R=20Ω,R2=6.5Ω,在工频下,当调节触点C使Rac=5Ω时,电压表读数最小,其值为30V,此时电压源电压为100V,求Z。+-R2URZVdcbaV0100U令URRUZRRUUUac22acadcd01002055.65.630jZ由于调节触点C只能改变的实部,其值最小时,其实部为零,只有虚部,即cdUj30VcdU79.12j15.4Z解得