第14章作业解答

退出下一页上一页章目录总目录主页制作群解：2212212221211sKsKsKsssFP37714-3求下列各函数的原函数。⑴⑶2211ss545622sssss⑴令，有为单根，为二重根，设0sD11p22p111ssFsK12112ss22212ssFsK1112ss22222ddssFssK111dd2ssstttttf22eee2212111ssssF退出下一页上一页章目录总目录主页制作群1j21j2545632122sKsKsKssssssF⑶令，有为单根，为共轭复根，设0sD01p1j2,1j232pp01sssFK15456022sssss2'2pssDsNK12cose21tKtft5456⑶22sssss90j1j222e58356sssss90j3eK90cose212ttttsine212退出下一页上一页章目录总目录主页制作群P37714-5图示电路原处于零状态，t=0时合上开关S，试求电流iL。解：+-V50LiL0St50μF100H34+-s50sILsLRsC1sI1sI200,00CLuissRIsIsLR5021ssIsCRsRI501217500200750021ssssIsILAe5.0e5.11150501ttL-LsItiL1505.0505.11sss退出下一页上一页章目录总目录主页制作群解：P37714-6图示电路，已知时将开关S闭合，求时的。0t0,0A0tiLtuL+-Ve10t1H0St+-Lu+-12uΩ4+-1uΩ41R2R+-110ssL+-sUL+-sU12+-sU1sLsURssUsLRR1112121101116151ssssUVe18e361ttL-LsUtuLsUsUsUsUL111326115sss61813ss退出下一页上一页章目录总目录主页制作群解：P37814-7图示电路，设电容上原有电压电源电压。求S合上后电感中的电流。μF1000,H1.0,10,30,V20021SCLRRUtiL,V1000CU+-SULiLSC1R+-0CU2R+-s200sILsL1R-2R+s100sC1+-0LLi5A1030200021SRRUiLV10000CCUussCsLRLissUsCRsLRLn100020011112125220010235005sssssILsLRULissInLL110200Ae150052001tL-LtsItiL