三角函数两角和差公式及其基本练习题一公式及技巧:1、和差公式:(1)sinsincoscos)cos(;(2)sincoscossin)sin()3sin(cos23sin21xxx)4sin(2cossinxxx)sin(5)sin(43cos4sin322xxxx)sin(cossin22xbaxbxa(3)tantan1tantan)tan()tantan1()tan(tantan2、二倍角(半角)公式:(1)22sincos2cos1cos2222cos1cos22cos12cos2sin2122cos1sin22cos12sin(2)cossin22sin2sin21cossin(3)2tan1tan22tancos1cos12tansincos1cos1sin备注:常用技巧或知识:(1)角的关系:)(2)()(4)4((2)代换:1=12cos12sin20sin20sin4cos24sin24tan2200(3)韦达定理:)0(02acbxax有两根21、xx,则有acxxabxx2121,(4)由三角函数线及其三角形三边关系有:xxxxcossin1cossin与一正一负;xxxxcossin1cossin与同号;xxxxcossin1cossin与有一个为零。二、填空题:1.21____16sin14cos16cos14sin0000;2.函数xxycos24sin7的最大值为____25___;3.比较大小:0036cos36sin<0038cos38sin;4.___426__15sin0;5.__422__8sin2;6.___161_80cos60cos40cos20cos0000;7.___3_15tan115tan100;8.求值__3__25tan35tan325tan35tan0000;9.已知)23,(,53cos),,2(,32sin,15538)cos(;10.已知锐角、满足1312)cos(,43sin,则527536sin;三、解答题:11.若,2)3tan(求tan.1183512..若51cossin,求2sin252413.若tan、tan为方程01532xx的两根,求)tan(.4514.锐角、满足,3tan,2tan求;4315.已知),2,23(化简sin1sin12cos216.求函数22sincossin2cosxxxxy的最大值.2)4sin(2x