20101125276TelecomPowerTechnologyNov.25,2010,Vol.27No.6:2010-06-23:孟建辉(1987-),男,河南扶沟县人,大连交通大学电力电子与电力传动专业硕士研究生,研究方向:功率变换技术及应用。刘文生(1961-),男,大连交通大学电气信息学院教授,研究方向:电力牵引与电力传动。:1009-3664(2010)06-0033-03DCMCCM,(,116028) :反激式变换器有两种工作模式,一种是不连续导通工作模式(DCM),另一种是连续导通工作模式(CCM)。文中在分析其工作原理的基础上,通过推导计算两种模式下主要参数的大小,从不同的方面来分析二者的优缺点,进而得出相关的结论。:反激式变换器;不连续导通工作模式;连续导通工作模式:TM461.5:ATheAnalysisandComparisonbetweenDiscontinuousConductionModeandContinuousConductionModeofFlybackConverterMENGJian-hui,LIUWen-sheng(DalianJiaotongUniversity,Dalian116028,China)Abstract:Therearetwomodesinflybackconverter,oneisthediscontinuousConductionconductionmode(DCM),andtheotheristhecontinuousconductionmode(CCM).Beforeanalyzingthebasisofflybackconverterandcalculatingthemainparameteroftwomodes,thispaperanalyzestheadvantagesanddisadvantagesofDCMandCCMfromdifferentas-pects,someinterrelatedconclusionsaregivenatlast.Keywords:flybackconverter;DCM;CCM0 Buck-boost,,,。,(DCM)(CCM),。,,。1 1[1],,。(a);(b)1;(c)21 (1)1:t0~tl。T。T,。VD。,C。(2)2:tl~ts。T,。T,,VD。,。,,DCM;,CCM。2。(a)CCM (b)DCM2 2 DCMCCM2.1 30W·33· 20101125276TelecomPowerTechnologyNov.25,2010,Vol.27No.6DCMCCM,。:Po=300W,Uo=12V,f=50kHz,Udc=210V,Udc(max)=365V。(1)DCM,Np,,di/dt=(Udc-1)/Lp,1V,Lp。,Ip=(Udc-1)Ton/Lp。E=Lp(Ip)22(1) ,TPin=12Lp(Ip)2T=[(Udc-1)Ton]22TLp≈(UdcTon)22TLp(2) (1),(2),,UdcTon。Ton,Udc(min)。Ip=Udc(min)Ton/Lp。η=80%,Pin=1.25Po=1.25Uo2Ro=12LpIp2T=(UdcTon)22TLp(3) Uo=UdcTonRo2.5TLp(4) 1V,[2]Ums(max)=Udc(max)+NpNs(Uo+1)(5) ,Ums(max),0.3UdcUms(max),30%。700VMOSFET,Ums(max)520V,NpNs=Ums(max)-Udc(max)Uo+1=520-36512+1=12(6) 1V,(Udc(min)-1)ton=(Uo+1)NpNstr(7),tr。,Tdc,80%。ton+tr=0.8T(8) (6)、(7)ton=(Uo+1)(Np/Ns)(0.8T)(Udc(min)-1)+(Uo+1)(Np/Ns)(9) ton=(Uo+1)(Np/Ns)(0.8T)(Udc(min)-1)+(Uo+1)(Np/Ns)=13×12×0.8×20×10-6209+13×12=6.82μs(10) Lp=R2.5T(Udc(min)TonUo)2=4.82.5×20×10-6(210×6.82×10-612)2μH=1367.46μH(11)Ip=Udc(min)TonLp=210×6.82×10-61367.46×10-6A=1.05A(12) Is=(Np/Ns)Ip=12×1.05A=12.57A(13) (2)CCM1V,(Udc(min)-1)Ton=(Uo+1)NpNsToff(14) Ton+Toff=T,Uo=[(Udc(min)-1)(Ns/Np)(Ton/T)1-Ton/T]-1(15) ,(ton/T)=0.43,ton=8.60μs,toff=11.40μs。Icsr,:Po=UoIcsrToffT=UoIcsr(1-Ton/T)(16) Icsr=PoUo(1-Ton/T)(17) Icsr=PoUo(1-Ton/T)=3012×(1-0.47)A=4.31A(18) Po=0.8Pin,Icpr,Pin=1.25Po=UdcIcprTonT(19) Icpr=1.25PoUdc(Ton/T) ·34· 20101125276: DCMCCMTelecomPowerTechnologyNov.25,2010,Vol.27No.1Icpr=1.25PoUdc(min)(Ton/T)=1.25×30176×0.47A=0.43A(20) ,Po(min)Icpr(min)Icpr(min)=dIp2=1.25Po(min)Udc(min)(Ton/T)(21) dIp=2.5Po(min)Udc(min)(Ton/T)(22) ,dIpdIp=(Udc(min)-1)Ton/Lp, Lp=(Udc(min)-1)TondIp=(Udc(min)-1)(Udc(min))(Ton)22.5Po(min)T(23),Po(min)。Lp=(Udc(min)-1)(Udc(min))(ton)22.5PoT=175×176×(9.40×10-6)22.5×30×20×10-6μH=2164.07μH(24)2.2 ,1。1 DCMCCMDCMCCM/μH1367.462164.07/A1.050.43/A12.574.31 。(1),,MOSFET。DCM,CCM,MOSFET,,,CCMDCM。(2),,。。,。CCM[3]:WaAc=Pomax1-Dmin1-Dmax(1-Dmax+Dmax)F(λ)BmJKfη2×106cm4(25) DCM:WaAc=23Pomax(1-Dmax+Dmax)BmJKfη1×106cm4(26),Wa;Ac;Pomax;Dmax/;Dmin/;η1/;η2/;Bm;K;J;F(λ)=1+λ/2λ;λ=■imIm—。CCMDCM,。WaAc(DCM)WaAc(CCM)=23(1-Dmax)(1-Dmin)1F(λ)(27) η1=η2,λ=0.5,F(λ)=2.5,WaAc(DCM)WaAc(CCM)=0.46×1-Dmax1-Dmin(28) ,DCMCCM。,DCMCCM,3,。,DCM,Bm。DCMCCM,。(a)CCM (b)DCM3 (3)LC1,DCM,,C,Resr,Ip(Np/Ns)Resr。,-,0.5μs(Resr(38)·35· 20101125276TelecomPowerTechnologyNov.25,2010,Vol.27No.64 SPLLSimulink 5,2,1,,SPLL。5 SPLL 6CCSGraph。DSP2407,,,0.45℃,。6 3 SPLL,DSP2407,SPLLSimulink,。:[1] RolandEBest.[M].:,2007.[2] ,.[J].,2007,(5):21-23.[3] , , , .[J].,2007,(6):28-30.[4] .DSP[D].,2004.(35)),。,,。,LC。DCM,LC。DCMLC,DCMCCM。(4),EMI。,DCM,,。3 ,CCM,,;。DCM;,CCM,LC,。,,,。:[1] .[M].:,2006.[2]AbrahamI.Pressman.,.[M]..:,2005.[3] .[M].:,2010.·38·