《电工电子技术(少学时)》(第4版-林平勇)习题答案-xiti12-10

12.10按下列各运算关系式画出运算电路，并计算各电阻的阻值，括号中的反馈电阻Rf和电容Cf是已给出的。（1）u。＝-3ui（Rf=50kΩ）；（2）u。=-（ui1十0.2ui2）（Rf=100kΩ）；（3）u。=5ui（Rf=20kΩ）；（4）u。=0.5ui（5）u。=2ui2-ui1（Rf=10kΩ）；（6）∫-=dtuuio200（CF=0.1uF）（7）dtudtuuiio∫∫--=21510（CF=1uF）解：（1）)50(3Ω=-=kRuufio)(7.163501Ω===kARRuf)(5.127.16//50//12Ω===kRRRf（2）)100()2.0(21Ω=+-=kRuuufiio根据)(2311ififouRRuRRu+-=)(1001Ω==kRRf)(5002.01002.03Ω===kRRf)(45.45500//100//100////313Ω===kRRRRf（3）)20(5Ω==kRuufio根据ifouRRu)1(1+=)(51520151Ω=-=-=kRRf)(45//20//12Ω===kRRRf∞+-+RfR1R2uiuo∞+-+RfR1R2ui1uoui2R3ui∞+-+RfR1uoR2（4）iouu5.0=iuRRRu323+=++++=uRRuufo1ifouRRRRRu3231)1(++=取：RRRRf===31RR32=（5）)10(212Ω=-=kRuuufiio根据1121)1(ififouRRuRRu-+=)(101Ω==kRRf)(510//10//12Ω===kRRRf（6）)1.0(200FCdtuufiom=-=∫根据∫-=dtuCRuifo11)(50101.020011200611Ω=××==-kRCRf)(5012Ω==kRR（7）)1(51021FCdtudtuufiiom=--=∫∫根据∫∫--=dtuCRdtuCRuififo22111)(1001010110161Ω=×==-kCRf)(20010515162Ω=×==-kCRf)(67200//100//213Ω===kRRR∞+-+RfR1R2ui1uoui2∞+-+CfR1R2uiuo∞+-+CfR1R3ui1uoui2R2ui∞+-+RfR1uoR2R3