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1%例题3-1l1=80r1=0.21x1=0.416b=2.74/1000000vn=110S1=15dp0=40.5dps=128vs=10.5i0=3.5sldb=30+12isldc=20+15i%（1）计算参数并作出等值电路rl=0.5*l1*r1xl=0.5*l1*x1bc=2*l1*bdqb=-0.5*bc*vn*vnrt=0.5*dps*vn^2/1000/S1^2xt=0.5*vs*vn^2/100/S1dq0=i0*S1/100dp1=2*dp0/1000dq1=2*dq0*is0=dp1+dq1sb=sldb+s0+dqb*isc=sldc%（2)计算由母线A输出的功率dst=(abs(sc)/vn)^2*(rt+xt*i)%变压器绕组中的功率损耗为sc1=sc+dsts11=sc1+sbdsl=(abs(s11)/vn)^2*(rl+xl*i)%线路中的功率损耗为s1=s11+dslsa=s1+dqb*i%由母线A输出的功率为%（3）计算各节点电压p1=52.54q1=32.1va=117%线路中电压降落的纵分量和横分量分别为：dvl=(p1*rl+q1*xl)/vapvl=(p1*xl-q1*rl)/vavb=sqrt((va-dvl)^2+(pvl)^2)%b点电压为pc=20.18qc=17.19vcc=112%变压器中电压降落的纵分量和横分量分别为：dvt=(pc*rt+qc*xt)/vbpvt=(pc*xt-qc*rt)/vbvc1=sqrt((vb-dvt)^2+(pvt)^2)%归算到高压侧的c点电压vc=vc1*vcc/vn%变电所低压母线c的实际电压l1=80r1=0.2100x1=0.4160b=2.7400e-006vn=110S1=15dp0=40.5000dps=128vs=10.5000i0=3.5000sldb=30.0000+12.0000isldc=20.0000+15.0000irl=8.4000xl=16.6400bc=4.3840e-004dqb=-2.6523rt=3.4418xt=42.3500dq0=0.5250dp1=0.0810dq1=0+1.0500is0=0.0810+1.0500isb=30.0810+10.3977isc=20.0000+15.0000idst=0.1778+2.1875isc1=20.1778+17.1875is11=50.2588+27.5852idsl=2.2818+4.5201is1=52.5406+32.1053isa=52.5406+29.4530ip1=52.5400q1=32.1000va=117dvl=8.3374pvl=5.1677vb=108.7854pc=20.1800qc=17.19003vcc=11dvt=7.3305pvt=7.3122vc1=101.7180vc=10.1718%例题3-2s2=0.3+0.2is3=0.5+0.3is4=0.2+0.15iz12=1.2+2.4iz23=1.0+2.0iz24=1.5+3.0ivn=10%(1)求线路始端功率ds23=(abs(s3)^2/vn^2)*z23ds24=(abs(s4)^2/vn^2)*z24s23=s3+ds23s24=s4+ds24s112=s23+s24+s2ds12=(abs(s112)/vn)^2*z12s12=s112+ds12%（2）求线路各点电压dv12=(real(s12)*real(z12)+imag(s12)*imag(z12))/(1.05*vn)v2=1.05*vn-dv12dv24=(real(s24)*real(z24)+imag(s24)*imag(z24))/v2dv23=(real(s23)*real(z23)+imag(s23)*imag(z23))/v2v3=v2-dv23v4=v2-dv24%（3）根据上述求得的线路各点电压，重新计算各线路的功率损耗和线路始端损耗ds23=(abs(s3)/v3)^2*z23ds24=(abs(s4)/v4)^2*z24s23=s3+ds23s24=s4+ds24s112=s23+s24+s2ds12=(abs(s112)/v2)^2*z12%从而可得线路始端功率s12=s112+ds12s2=0.3000+0.2000is3=0.5000+0.3000is4=0.2000+0.1500iz12=1.2000+2.4000iz23=1.0000+2.0000i4z24=1.5000+3.0000ivn=10ds23=0.0034+0.0068ids24=0.0009+0.0019is23=0.5034+0.3068is24=0.2009+0.1519is112=1.0043+0.6587ids12=0.0173+0.0346is12=1.0216+0.6933idv12=0.2752v2=10.2248dv24=0.0740dv23=0.1092v3=10.1155v4=10.1507ds23=0.0033+0.0066ids24=0.0009+0.0018is23=0.5033+0.3066is24=0.2009+0.1518is112=1.0042+0.6585ids12=0.0166+0.0331is12=1.0208+0.6916i%例题3-3vn=10l1=10l2=4l3=3l4=2va=10.5vb=10.4z1=0.17+0.38*iz2=0.45+0.4*i%的线路等值阻抗zl1=10*z1zl2=4*z1zl3=3*z1zl4=2*z2%求C和D点的运算负荷，为sc1=2600+1600*ise=300+160*isd1=600+200*isd2=1600+1000*i5dsce=(abs(se/1000)/vn)^2*zl4*1000sc=sc1+se+dscesd=sd1+sd2%循环功率z11=0.17-0.38*iscc=1000*(va-vb)*vn/(17*z11)sac=(real(sc)*7+imag(sc)*7*i+real(sd)*3+imag(sd)*3*i)/17+sccsbd=(real(sc)*10+imag(sc)*10*i+real(sd)*14+imag(sd)*14*i)/17-sccs1=sac+sbds2=sc+sdsdc=sbd-sd%C点位功率分点，可推测出E点电压最低点，进一步可求得E点电压dsac=(abs(sac/1000)/vn)^2*zl1*1000s1ac=sac+dsacdvac=(real(s1ac/1000)*real(zl1)+imag(s1ac/1000)*imag(zl1))/vavc=va-dvacsce=se+dscedvce=(real(sce/1000)*real(zl4)+imag(sce/1000)*imag(zl4))/vcve=vc-dvcevn=10l1=10l2=4l3=3l4=2va=10.5000vb=10.4000z1=0.1700+0.3800iz2=0.4500+0.4000izl1=1.7000+3.8000izl2=0.6800+1.5200izl3=0.5100+1.1400izl4=0.9000+0.8000isc1=2.6000e+003+1.6000e+003ise=3.0000e+002+1.6000e+002isd1=6.0000e+002+2.0000e+002isd2=1.6000e+003+1.0000e+003idsce=1.0404+0.9248isc=2.9010e+003+1.7609e+003isd=2.2000e+003+1.2000e+003iz11=0.1700-0.3800iscc=5.7703e+001+1.2898e+002isac=1.6405e+003+1.0658e+003isbd=3.4606e+003+1.8951e+003is1=5.1010e+003+2.9609e+003i6s2=5.1010e+003+2.9609e+003isdc=1.2606e+003+6.9509e+002idsac=6.5062e+001+1.4543e+002is1ac=1.7055e+003+1.2113e+003idvac=0.7145vc=9.7855sce=3.0104e+002+1.6092e+002idvce=0.0408ve=9.7447%例题3-4r1=0.27x1=0.423b1=2.69/1000000r2=r1x2=x1b2=b1r3=0.45x3=0.44b3=2.58/1000000l1=60l2=50l3=40vn=110snb=20ds0b=0.05+0.6*irtb=4.84xtb=63.5snc=10ds0c=0.03+0.35*irtc=11.4xtc=127sldb=24+18*isldc=12+9*i%（1）计算网络参数及制定等值电路Z1=l1*(r1+x1*i)%线路1B1=l1*b1dqb1=-B1*vn^2/2Z2=l2*(r2+x2*i)%线路2B2=l2*b2dqb2=-B2*vn^2/2Z3=l3*(r3+x3*i)%线路3B3=l3*b37dqb3=-B3*vn^2/2ztb=(rtb+xtb*i)/2%变电所bdS0b=2*ds0bztc=(rtc+xtc*i)/2%变电所cdS0c=2*ds0c%（2）计算节点b和c得运算负荷dstb=(abs(sldb)/vn)^2*ztbsb=sldb+dstb+dS0b+dqb1*i+dqb3*idstc=(abs(sldc)/vn)^2*ztcsc=sldc+dstc+dS0c+dqb3*i+dqb2*i%（3)计算闭式网络的功率分布s1=(sb*(conj(Z2)+conj(Z3))+sc*conj(Z2))/(conj(Z1)+conj(Z2)+conj(Z3))s2=(sc*(conj(Z1)+conj(Z3))+sb*conj(Z1))/(conj(Z1)+conj(Z2)+conj(Z3))s12=s1+s2sbc=sb+scs3=sb-s1%（4）计算电压损耗dsl1=(abs(s1)/vn)^2*Z1sa1=s1+dsl1va=117dv1=(real(sa1)*real(Z1)+imag(sa1)*imag(Z1))/vavb=va-dv1r1=0.2700x1=0.4230b1=2.6900e-006r2=0.2700x2=0.4230b2=2.6900e-006r3=0.4500x3=0.4400b3=2.5800e-006l1=60l2=50l3=40vn=110snb=20ds0b=0.0500+0.6000irtb=4.8400xtb=63.5000snc=10ds0c=0.0300+0.3500irtc=11.4000xtc=127sldb=24.0000+18.0000i8sldc=12.0000+9.0000iZ1=16.2000+25.3800iB1=1.6140e-004dqb1=-0.9765Z2=13.5000+21.1500iB2=1.3450e-004dqb2=-0.8137Z3=18.0000+17.6000iB3=1.0320e-004dqb3=-0.6244ztb=2.4200+31.7500idS0b=0.1000+1.2000iztc=5.7000+63.5000idS0c=0.0600+0.7000idstb=0.1800+2.3616isb=24.2800+19.9607idstc=0.1060+1.1808isc=12.1660+9.4427is1=18.6410+15.7972is2=17.8050+13.6062is12=36.4460+29.4034isbc=36.4460+29.4034is3=5.6390+4.1