泵站更新改造的复核计算分析

2014542HeilongjiangScienceandTechnologyofWaterConservancyNo.5.2014TotalNo.421007－7596201405－0025－041540021991。、。TV675BＲeviewCalculationandAnalysisforＲenovationofPumpingStationGUOCheng-qianHeilongiangProvinceJiamusiCityWaterConservancy＆HydropowerInvestigationDesignandＲesearchInstituteJiamusi154002ChinaAbstractThepumpingstationsinZhenxingquanDistrictTangyuanCountyandJiamusiCityhavealowguaranteeratesincetheywereputintooperationin1991notuptothedesignofirrigationcapacity.Themainreasonsfortheproblemsarethepumpsagingpumpinghousesdisrepairetc.sotheymustberenovatedandupgraded.Throughanalyzingandcalculatingrelevantreviewcalculationresultsandcountermeasuresareputforwardsoastoprovidethebasisforthetechnologicalrenovationofthepumpingstations.Keywordspumpingstationreviewsafetystabilitystrength2013－12－05郭承乾(1981－)，男，甘肃环县人，工程师。019841991、、。、、、。、、。11.1、、1。、、1。1/kW/m3·s－110057.8Ⅲ330100。、2。—52—2014542HeilongjiangScienceandTechnologyofWaterConservancyNo.5.2014TotalNo.422Hst/m8.21.189.87Q/m3·s－17.161.233。3KcKcη1.251.102.001.101.052.502《》①②③④⑤⑥2。33.13.1.13.1.1.1J＜J。J=△H/L1Lm△H、m。3.1.1.2。3。4△H/mL/mJJ10.0243.50.230.25。3.1.23.1.2.12L=Kh2LmKh。L=3.58v0v2－10.41D03Lmv0m/svm/sD0m。3.1.2.2B≥2～3D。3.1.2.3PP=10～20cm。3.1.2.4h=1－2v022g4hmv0m/s。3.1.2.5=－hmin+D0+P5hmin。3.1.2.6Lp=Kq△槡槡H6qm3/s△HmKK=10。。4。4/m/m/m/m/m/m0.570.84.6103.1103.2、3.2.1。Q=8.95m3/s。V=1nＲ2/3i1/27—62—5n0.0275Ｒi1/1000。Q=A×V=5.23m3/s＜8.95m3/s。3.2.2《》≤40°1∶4。30～50。。3.2.3V=1nＲ2/3i1/28n0.0275Ｒi。Q=A×V9。3.33.3.1。、、、、、、。3.3.23.3.2.1。3.3.2.2。。3.3.2.31Kf=VU≥Kf10KfVTUTKfKf=1.10Kf=1.05。2Kc=f'G+G0AH≥Kc11KcGTHTf'C0Am2Kc3Kc=1.25Kc=1.101.05。3《》GB/T50265—97。4Pminmax=GA1±6eB≤P12PminPmax≤φ13PminmaxkN/m2MkN·mBmeme=MGPP=220kPaφ2.03.5。3.3.35。、。3.4。《》《》。—72—2014542HeilongjiangScienceandTechnologyofWaterConservancyNo.5.2014TotalNo.425KcKf/kN·m2PmaxPmin3.253.7096.4060.401.607.383.8089.2056.501.582.852.9085.0052.601.623.4.15.2m400mm800mm。18.2MPa12mmC15II。3Ⅱγo=1.0Ψ=1.0γd=1.2。25kN/m3γg=1.05γg=1.051.4kN/m2γq=1.21.3。3.4.21。2。3。3.4.35.2m5.5m。1q1=8.4kN/m2P2=53.5kN3q2=10.24kN/m4q3=1.68kN/m。。M=Pab/LM－qL2/8M=Pa2b/L2M=qL2/12。Mmax=150.40kN·m。3.4.4αs=γd×Mfc×b×h02ξ=1－1－2×α槡sAs=fc×ξ×b×h0fyρ=Asb×h0＞ρmin14fcN/mm2αsξAsmm2。982mm23Φ16As=603mm2＜982mm2。。。3.5《》GB18306—2001＜0.05g0.35gⅥ。《》DL5073—20006。3.6330a100a。77.10m77.77m。75.40m77.10m。。4。。。1．SL316—2004S.2005．2．GB/T50510—2009S.2010．—82—