14.2整式的乘法1.单项式与单项式相乘一、选择题1.计算2322)(xyyx的结果是()A.105yxB.84yxC.85yxD.126yx2.)()41()21(22232yxyxyx计算结果为()A.36163yxB.0C.36yxD.36125yx3.2233)108.0()105.2(计算结果是()A.13106B.13106C.13102D.14104.计算)3()21(23322yxzyxxy的结果是()A.zyx663B.zyx663C.zyx553D.zyx5535.计算22232)3(2)(bababa的结果为()A.3617baB.3618baC.3617baD.3618ba6.x的m次方的5倍与2x的7倍的积为()A.mx212B.mx235C.235mxD.212mx7.22343)()2(ycxyx等于()A.214138cyxB.214138cyxC.224368cyxD.224368cyx8.992213yxyxyxnnmm,则nm34()A.8B.9C.10D.无法确定9.计算))(32()3(32mnmyyxx的结果是()A.mnmyx43B.mmyx22311C.nmmyx232D.nmyx5)(31110.下列计算错误的是()A.122332)()(aaaB.743222)()(babaabC.212218)3()2(nnnnyxyxxyD.333222))()((zyxzxyzxy二、填空题:1..___________))((22xaax2.3522)_)((_________yxyx3..__________)()()3(343yxyx4.._____________)21(622abcba5.._____________)(4)3(523232baba6..______________21511nnnyxyx7.._____________)21()2(23mnmnm8.._______________)104)(105.2)(102.1(9113三、解答题1.计算下列各题(1))83(4322yzxxy(2))312)(73(3323cbaba(3))125.0(2.3322nmmn(4))53(32)21(322yzyxxyz(5))2.1()25.2()31(522yxaxyaxx(6)3322)2()5.0(52xyxxyyx(7))47(123)5(232yxyxxy(8)23223)4()()6()3(5aabababbba2、已知:81,4yx,求代数式52241)(1471xxyxy的值.3、已知:693273mm,求m.