5分钟教你正确理解电力系统中的正序负序零序

12333BC120A3334BC120A3331ABCACBUaUbUcabcUaacabUUUU2j120e212331,12023341/32BCA3B120C1203/3,A3BC3B120C1203/3,AABC1202402.1ABACABoCo0,2.2(1)AB120OBC120OC(2)OC(3)OC,O1A2.3(1)AB120OBC120OC(2)OC(3)OCA1AB120BA240120CA120240A0jUeB240jUeC120jUeacabUUUU21eeeesin120jcos120eej0-j3603j120-j2402-j240j12022CBAAAAIIIIII1111131220CBAACBAACBAAIIIIIIIIIIII2203131312ABC002002ACACACABABABIIIIIIIIIIII302211111AAACBAIIIIII0200200AAACCCCAAABBBBAAAAIIIIIIIIIIIIIIIIIIBCA34A0)0()1(1)2323()5.05.0(1)120sin240(sin)120cos240(cos1)120sin120(cos)240sin240(cos1111202402jjjjjeejjAAACBACBACBACBACBAAAAIIIIIIIIIIIIIIIIIII)0(31)0(311)1(31)1(313131313131312222031sin(+)=sincos+cossinsin(-)=sincos-cossinAUsinBUsin(-120)CUsin(+120)Ua+Ub+Uc=U(sin+sin(-120)+sin(+120))=U(sin+(sincos120-cossin120)+(sincos120+cossin120))=U(sin+2sincos120)=U(sin+2sin(-0.5))=020122acbaacabUUUUUUUU30