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1题卡号：M(O)-gen-e编码：JF11题目：编制杂货船的配积载计划评估时间：180分钟评估方式：实操评分标准：满分为50能力核算重量分配初配方案及检查计算指标绘积载图总计5%5%20%10%10%50%评估项目“货物积载与系固——杂货船配积载”题卡（适合于无限、近洋、沿海航区3000总吨及以上船舶大副/船长）“Q”轮第V0100W航次货运任务如下列“装货清单”所列。船舶计划于月日在上海港装货后开航。全航程中船舶吃水无水深限制，船舶航速17.5kn,船舶在始发港补足油水，无中途油水补给计划。船舶各液舱油水等储备量见“答题卷”中表-5，“Q”轮其他详细资料见附录。装货清单LoadingListofS.S/M.VQ关单号码S/ONo.件数及包装No.ofPKGS货名Description重量（t）Weightinmetrictons估计体积(m3)Estimatedspaceincu.m积载因数SF(m3/t)备注RemarksForLiverpoolS/O14300b/sCottonpiece棉布4306451.50S/O233530ctnsTextiles纺织品124049604.00S/O37985ctnsEarthenware搪瓷制品2004602.30S/O45000ctnsPorcelainware瓷器1505553.70S/O525000bgsTalcumpowder滑石粉125021251.702S/O64560d/sPeanutoil花生油114018121.59S/O711260d/sBeeshoney蜂蜜137516651.21S/O8438b/sSilkpiecegoods丝绸27903.33SpecialstowageS/O913490ctnsChinatea中国茶叶33010563.20Total105563614213368题卡号：O-gen-e编码：JF111题目：编制杂货船的配积载计划评估时间：180分钟评估方式：实操评估项目“货物积载与系固——杂货船配积载”答题卷姓名:Teacher学号：0001得分:一、核定航次货运任务与船舶载货能力是否相适应1.计算航次净载重量NDW，查取航次装货重量，并判别能否承运？夏季载重线-查船舶资料及表5、装货清单。tCGNDWLs120952483221480556519710=−−−−=−−Δ−Δ=∑Q=6142tNDWQ结论：能够承运。航次净载重量NDW大于航次装货重量。2.查取货物总体积及船舶总舱容，并判别能否承运？查表3、装货清单：∑∑==331336819591mVmVcichi3∑∑cichiVV结论：能够承运。船舶总舱容大于货物总体积。3.船舶其他装载能力是否满足要求？本航次s/o8丝绸装于贵重舱,无其它如集装箱,危险货物,冷藏货物,重大件等特殊装载要求的货物。结论：能够承运。经核定航次货运任务与船舶载货能力相适应。二、确定航次货重在各货舱、各层舱的分配控制数各货舱配货重量核算表表-1离港别舱别数量（t）No.1No.2No.3No.4No.5合计各舱容占总值百分比(%)9.36%25.77%27.87%22.47%14.53%100%各舱装载重量调整值(t)115314339274147各舱装货重量上下限允许范围(t)690/4601897/12692051/13731654/11061039/745离上海港各舱实际装货重量(t)5201815147015607776142各舱装货重量上下限允许范围(t)调整值±×=%xQPi//离港各舱实际装货重量(t)P=6142×9.36%=575±1154各层舱配货重量核查表表-2二层舱舱层及离港港别离上海港离港离港实配重量(t)/所占百分比(%)第一次1730/28.17（二层舱重量之和）/（÷6142）调整后2017/32.84三、确定货物的舱位和货位（货物配舱）货物配舱的基本要求：（供参考，评估员按正式积载图评分）1.为满足稳性、纵强度和吃水差的要求，各舱实配货物重量应在上、下限范围内，上、下层舱配货重量比应保持在30%∼35%:65%∼70%。2.合理确定不同货物的舱位和货位；3.忌装货物之间应进行妥善隔离；4.无重货压轻货，易碎品受压现象；5.各舱室实际配货体积至少需小于该舱舱容20m3；6.满足装卸顺序要求，先卸港货不被后卸港货堵住；同一卸货港，不存在先卸港被后卸港货堵住现象。7.各卸港货物的装载左右均衡，船舶无初始横倾角；货物的装载左右均衡，船舶无初始横倾角。四、对初配方案进行全面核查各货舱配货容积核查表表-3No.1No.2No.3No.4No.5别二层底二层底舱二层底舱二层底舱贵二层底舱合计货舱容积10308041789326016303830131230902591461112619591配货体积980760176016651056181212402125901235645133685五、离始发港状态下船舶的稳性、纵向受力和吃水差的核查与调整说明：操作级评估仅限于表-5中非*列的计算和查表，以及下列3中稳性校核。船舶载荷力矩计算表表-5重心距舯距离Xi(m)纵向重量力矩PiXi(t⋅m)*项目重量Pi(t)重心高度Zi(m)舯前+舯后-垂向重量力矩PiZi(t⋅m)舯前+舯后-载荷对舯弯矩|PiXi|(t⋅m)*No.1二层舱33011.8553.183910.517549.417549.4底舱1906.9752.381324.39952.29952.2No.2二层舱44011.4232.185024.814159.214159.2底舱13755.5131.307576.2543037.543037.5No.3二层舱33011.188.03689.426402640底舱11405.357.85609989498949No.4二层舱31011.1713.873462.74299.74299.7底舱12505.3713.796712.517237.517237.5No.5二层舱60711.5455.557004.7833718.8533718.85底舱1707.2454.251230.89222.59222.5货物小计614246035.0396287.364478.55160765.85续表-5项目重量Pi(t)重心高度Zi(m)重心距舯距离Xi(m)垂向重量力矩PiZi(t⋅m)纵向重量力矩PiXi(t⋅m)*载荷对舯弯矩|PiXi|(t⋅m)*自由液面倾侧力矩ρix(t⋅m)*No.1燃油舱(左)2030.777.6115615451545880.0No.1燃油舱(右)2530.767.61192194119411566.0No.2燃油舱(左)1640.7713.8812622762276No.2燃油舱(右)2060.7613.9515728742874油燃油深舱(左)836.2543.81819363636366燃油深舱(右)836.2543.8151936363636燃油沉淀舱(左)49.57.1243.85352217121717燃油沉淀舱(右)49.57.1243.85352217121717燃油日用柜(左)2510.7613.8526934634614燃油日用柜(右)2110.6444.0022392492414柴油舱(左)941.0130.78959595210.0柴油舱(右)1161.0232.57118118118225.0柴油日用柜(左)1210.7039.35128472472柴油日用柜(右)1210.7039.35128472472柴油沉淀柜3310.7341.5135313701370滑油循环舱201.3237.6026752752滑油储存柜1710.7043.29182736736汽缸油柜(左)7.510.7043.8580329329汽缸油柜(右)6.510.6243.9569286286污滑油舱250.6734.5017863863小计48040614862352727013饮水机6011.1025.506661530153041.5淡水舱(左)1013.3250.803355131513172.4淡水舱(右)1293.2750.6942265396539123.5锅炉水舱191.0740.312076676621.6汽缸冷水舱130.9227.4012356356淡水小计32214551432214322粮食810.834.086272272船员和行李1015.530.0155300300备品1013.015.0130150150船舶常数22010.80.0237600其他小计2482747150572722空船55659.07-8.635047548026合计（排水量）13757104773999231509252028223182从船舶资料中查取：查表引数（排水量）dm(m)*Xb（m）*MTC(tm/cm)*KM(m)GMc(m)137576.8-0.0481878.720.1571.计算离港时的吃水差t,（要求t=-0.6∼-0.8m,该步仅限于管理级评估做）结论：不满足要求。调整方法：（仅需用文字定性说明）本航次船舶为半载，可在首尖舱打压载水，使离港时的吃水差调整在-0.6∼-0.8m之内。也可从尾向首移动适量货物。2.核算船舶离港时的纵强度(该步仅限于管理级评估做)202822.859.811989692.2iiPXKNmΣ=×=⋅查船舶强度曲线图，船舶处于有利中拱状态。结论：满足纵强度要求。调整方法：（仅需用文字定性说明）无需调整。3.计算船舶离港时GM值，判别稳性是否符合要求：0104773.037.61613757iiPZKGmΣ===Δ00xfiGMmρδ∑==Δ008.727.61601.104fGMKMKGGMmδ=−−=−−=0.20.150.200.35CGMm+=+=∵0.20CGMGM+结论：满足稳性衡准要求。mXPXiig71.31357555.1509253.99923−=−=ΔΣ=mMTCXXtbg69.2187100)048.071.3(13757100)(−=×+−=−Δ=831820.23113757xfiGMmρδ∑===Δ08.727.6160.2310.873fGMKMKGGMmδ=−−=−−=调整方法：（仅需用文字定性说明）无需调整。体积计算iiiVPSF=×如：1号舱二层舱的纺织品V=130*4=520m3件数计算iP=×总件数件数总重量件数=（3353/1240）*130=351.52=3529六、绘制正式积载图货物积载图船名(M/V)“Q”轮航次(Voyno.)V0100WSTOWAGEPLAN自(Form)上海到(To)Liverpool备注Remarks大副签章（SIGNATUREOFCHIEFOFFICER）MasterS/O1棉布430t(645m3)4300b/sS/O5滑石粉1250t(2125m3)25000bgsS/O6花生油1140t(1812m3)4560d/sS/O7蜂蜜1375t(1665m3)11260bgsS/O2纺织品310t(1240m3)8382ctnsS/O4瓷器150t(555m3)560pcsS/O2纺织品170t(680m3)4597ctnsS/O7蜂蜜1375t(1665m3)11260bgsS/O5滑石粉1250t(2125m3)25000bgsS/O7蜂蜜1375t(1665m3)11260bgsS/O2纺织品190t(760m3)5138ctnsS/O2纺织品130t(520m3)3515ctnsS/O3搪瓷200t(460m3)7985ctnsS/O2纺织品440t(1760m3)11998ctnsS/O9茶叶330t(1056m3)13490ctnss/o8丝绸27t(90m3)438b/s10附：积载图草稿货物积载图STOWAGEPLAN2226/1548t1461m31126m31312m33090m33830m