当前位置:首页 > 行业资料 > 其它行业文档 > 第26届全国中学生物理竞赛决赛试题理论部分及标准答案
265201.()yfx=yamk222()yCxamgp=--C2.RAB712R3.500nm50001.5rmm=d30mm4.0USCIp-n0U=0ln1SCSIkTUeI⎛⎞=+⎜⎟⎝⎠ekTSIp-n20125327-30mm50441151.()Fr()()kFrFraa=krab2.1.//,,rrttab==////00limlimttrrvvttaabbΔ→Δ→ΔΔ===ΔΔ1////2200limlimttvvavttaabbΔ→Δ→ΔΔ===ΔΔ(2)()maFr=(3)//()maFr=(4)2()()kFrFraa=412()kmaFrab-=5312kba-=62.2k=/laa=71/2tbtat==8/22/33lltt=915106105559520mqABAOdBO20kqumd=kyxAu0Bu0OdABrrr=-rrrrer=rr22()Arkqmaeiir=-⋅uururrr22()Brkqmaejjr=⋅uururrr122rkqmaer=rur2BAaaa=-ruuruurBA2BAm22kqUr=(3)BA200()kqLmdiujuimdmd=-×-+=rrr4222001()22kqkqEmujuidd=-++=rr5mrmumrreur2mmkqmrumdmd=(6)2222122mmkqkqmrurd+=(7)154rd+=82031045(6)(7)(8)21012,TT12,QQ12120QQTT+≤T0T1,T20Q,10Q010000QQTT-≤(1)2,Q12,Q(2)11012QQQ=+(3)120210210QQQTTT+-≤(4)102QQQ=+51,Q122120QQTT-+≤/01QQ=64501201102()()TTTQQTTT-≥-7/00201/0102()()QQTTTQTTT--≤-8104415xoynxEEi=urrirzBBk=urrkrzvtmvt-mxyxjyjenmEtωeBmw=xyxxymvmaeEevBt=---1yyxmvmaevBt=-2v0xyaa==2yxvvwt=3122(1)xeEvmtwt=-+4xxjnev=-5yyjnev=-6222(1)xneEjmtwt=-+2222(1)yneEjmwtwt=-+151220xyaa==234156378125Adyyx:022sin()sin()zxzxEEtppwll=-ωt,zxll1.zl2,1,2,3zdmml==…………..2.m=1zl3.yOBxxozbm=1yxzOAxOzBL.1E022sin()sin()zxzxEEtppwll=-1z=0dE=022,,1,2,3......zzddmmmppll===22.11sinsin[cos()cos()]2ababab=--+312EEE=+10122cos()2xzxzEEtppwll=--420122cos()2xzxzEEtppwpll=+--0l222201112xzcwlllp⎛⎞⎛⎞⎛⎞⎛⎞=+=⎜⎟⎜⎟⎜⎟⎜⎟⎝⎠⎝⎠⎝⎠⎝⎠5m=1,2,zdl=211()22zcdlwp=-(6)3,xxv2()21xxcvcdwlppw==⎛⎞-⎜⎟⎝⎠(7)POP=ROPθcosxRLRLccvq-=+822(11)(11cos)ccRLddppqww⎛⎞⎛⎞=----⎜⎟⎜⎟⎝⎠⎝⎠925510102556(6)486351.22306eaPcpe=ac014kep==8.854×10-12F•m-1,e=1.602×10-19Ct13.6HEeV=3109.10910mkg-=×2.3.50EGeV=,300ImA=L=432m,N=20B=1.27TP0224306eaPcgpe=×20Emcg=E20mc3.xOzqRP1gTΔ1Fma=12var=222014eFrpe=32008eUrpe-=413.6HEeV=-1105.2910rm-=×5602.1910/vms=×622306eaPcpe=6333240096ecmrpe=7tΔUUPtΔ=-Δ82220011()88eeUrrrrrpepe--=-=Δ-Δ9rΔr232222004124,cmrtrArrepepΔ=Δ=×Δ10322043cmAepe=r024rrpΔr0r03043rp0r0232230044cmrtepet=Δ=∑11111.5610st-=×122vc=(1)2Emc=(2)2var=(3)FeBc=(4)Fma=(5)ERecB=(6)QItneeΔ==(7)tΔ322424300263neueaReEccRgpgpee=×=8784504.34103neuutalnEIePWtRge===×Δ(9)402.1710utalPPWN==×(10)3:P2g2Rxg=(1)vcb=212Rttcg-=(2)AB2Rtcg′=(3)21Tttt′Δ=--(4)222011mcmcgb==-(5)10b-→221(1)bbg-=(6)43RTcgΔ=(7)209.5110Ts-Δ=×(8)351104512126718631345Rt2BAxt12/g
本文标题:第26届全国中学生物理竞赛决赛试题理论部分及标准答案
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