工程项目索赔的费用及满意度分析

华中科技大学硕士学位论文工程项目索赔的费用及满意度分析姓名：周颉申请学位级别：硕士专业：企业管理指导教师：何俊德20051031IIFIDICFIDICFIDICFIDIC;;;IIIAbstractClaimsmanagementisanimportantpartofprojectmanagement.Inprojectmanagementclaimisaverycomplexanddifficultwork,whichishighlyattentionbyboththeclientandthecontractorduetothefactthattheirbenefitswillbeinvolvedintheclaims.Asausefulstandardcontractmanagementmethod,ConditionsofContractwhichFIDICcompliesareacceptedbymostoftheinternationalprojects.Asthethirdparticipantinaengineeringproject,engineer'sspecialpositioncomestoadecisionthatengineersmustplayanimportantroleinclaimsandcounterclaimsbetweenproprietorsandcontractors.Intheintroductionofthisessay,thedefinitionofprojectclaimanbasicprocessoftheclaimsarediscussedingeneral,andatthesecondpart,acomparisonismadetotheclaimsbetweentheFIDICandtheconditionsofcontractforconstruction,andbuildamodelofclaimssystemforprojectmanager.Atlast,itdiscussedamodelofdecision-makingaboutprojectclaims.Theconclusiondrawnattheendoftheessayisphysicallyapplicableforotherinternationalprojects.Thestudyinthispapermainlyaimstoimprovemanagementlevelofconstructionclaimsforourprojectmanagersandmakecontributionstomanagementtheoriesofconstructionclaimsinourcountry.Keywords:FIDIC;claimmanagement;systemanalysis;satisfactiondegreeI(“”)::::11.1]1[WTOClaimLongman----]2[CounterclaimClaimantPlaintiffRespondentDefendant1.212342004612FIDICFIDIC1.3EngineeringindexEI]3[12CPM3]3[1.41991ICEJCTFIDIC]4[2FIDIC2.1FIDICFIDIC(FdrationInternationaleDesIngnieurs-Conseils)1913FIDIC460FIDIC1996FIDIC]5[1999FIDIC5/FIDICFIDICrainbow19951]8[1999FIDIC-EPC/FIDICFIDICFIDICFIDIC1995FIDIC1999[GF-1999-0201]FIDIC]6[FIDICWTOFIDIC]4[2.2GF-1999-0201]10[12FIDIC47342.3FIDICFIDICFIDICFIDICFIDIC1987553.1-53.31999FIDIC198742WTO1FIDIC23WTOFIDICFIDICFIDICFIDIC,,,,,,,,33.13.1.1,,,,,3:]23[,,,(3-1)O,S,H,E,A,,,:A(S,O,H,E)3.1.2,,,:1)2)3)4)3.1.3,,(),:,,,,(),,,,,,,,,,3-13.1.4,,,3.1.5SOE,,,,,,,,,,,,3,3,,,,,,,,,,,,,,,,,3.23.2.11)2)():1()2345673)()4)5)()1233.2.2:1);2):3)4)()3.33.3.1112321233.3.25]18[1282823453-2DAB4]20[4.11224.1.1,FIDIC,,,]21[:EOT()=at()-pT(),(),,(CPM),]21[:EOT=aD()-TF(),,,,,EOT(aD)TFaD,,,4.1.222d1d,()6004-1,()4-1,AKQ,1,,C3dN2d4-1(CPM),,4-2ADGL,pT22dAKQ,AES,QEF21d,21d4+7+3=14d,21-14=7d4-2CC3d,N,EOT3d,C8d4-3,4-3,CFQ,24d,24-22=2d,3d2d,24d4-3()4.24.2.11(1=(2=(3=(4=2=/100=+3==+41R2R]20[1R2R/12R2R=1R/1+1R5=+=++=/1006=1+=/7)(1)100(2)()4.2.21=2(1)(2)(3)(4)=3]12[4.2.38761503m785003m73699201()1284.53m750m5.53m1700m145161002914.753m402503m750m1500m19118826.253m125003m1700m2200m7812534061973114318162476431789173699207369920×[8/(100+8)]545920(7369920—545920)×[12/(100+12)]=731143731143÷18406192402503m1m3603m2828/603m0.473m6t43m2525/(4×2)3.133m:0.473.133.603m3.60120.43(3.60+0.43)4.0380.32(4.03+0.32)4.354.353m,4.753m402503m×4.353m1750881911883125003m10.623m23.913m34.53120.544.530.545.0780.415.483m4125003m×5.483m685007812543409440/(175088+68500)/4094400.60.62.4731143731143×(30.6)/1897486511750882685003974863410745,,,,,,,,,,,,,,,,,,,5.1:1)2)3)A,,:1)A(1A2A,mA)(m=1,2,)2),()A(1a2a,ma)3)H(1h,2h,th)4)ia,HP(ia),P(ia)[-1,1],iaHthP(ia)=-1iaHthP(ia)=0,iaHthP(ia)=1-11)(APAmA,mA,mA,P(ia)=F(mAH),P(ia)P(A)=1w)(1aP+2w)(2aP+)(mmaPw(5-1):1w+2w+mw=1,1w,2wmw0,mw(n=1,2),iaA,,mwiA,iAiH,P(ia),P(ia),p(A′)A,,,P(A′)=max()(1aP,)(2aP,)(maP),P(A)[0,1](5-2)P(A′)=0,A,A,P(A′)0,,,,]22[5.2,A,AH,,,,,,(SP)A,A,3:1),C2),T3)(,),IiHSCSTSISPCCCSSC∆∆−∆=CSC,CS=0TTTSST∆∆−∆=TST,TS=0IIISSI∆∆−∆=ISI,IS=0CSTSIS,AS,:S=1uCS+TSu2+ISu3(5-3)1u+2u+3u=1,1u,2u,3u,mA,S=maxmS(5-4)S0,,,A,P(ia),,P(ia),[1S,2S][0,1]P(ia)iaiHP(ia)CITP(ia)CITS=tStStS∈[1S,2S]S0S=0S[1S,2S],,P(ia),S,5.3,,,,,,(),,,,,,P(ia),CIT,P(ia)m,(1A2A,mA),(1A2A,mA),,3:1)AiHP(ia)2)3)P(CP,TP,IP),CP,TP,IP,[0,1],(5-3)1S=CP1u1CS+TP2u1TS+IP3u1IS,2S=CP1u2CS+TP2u2TS+IP3u2TS,3S=CP1u3CS+TP2u3TS+IP3u3TS,S=maxiS(i=1,2,,m),,,,,,,,,,,,,,,,,5.45.4.1∇84∇84-∇114160-180M∇8403315,04815,170312,,,,∇114043,,,045∇88,,5.4.2A,:1a,2a,3a1P(ia)(i=1,2,3)A,28.1123(1),(2)FIDICFIDIC:P(1a)=[0.8,1],P(2a)=[0.3,0.8],P(3a)=[0.8,1],,,,,,,1W=0.7,2W=0.2,3W=0.1,:P(A)=[0.7,0.96]02S1TT=[1T,2T]2T=57+51T=452C=[1C,2C]450221.383.14179.471.6394.7167.31527.52C=1527.51C=856.2,SC=813.8,ST=45,:CS=CCCS∆∆−∆=[0.05,0.87],TS=TTTS∆∆−∆=[0,0.38]S,1µ=0.5,2µ=0.5,S=1µCS+2µTS=[0.025,0.625]0,31A,2A,1A(CS,TS,S)=1A(0.05,0,0.025),2A(CS,TS,S)=2A(0.87,0.38,0.625):1P=0.9,2P=0.1,1AS=0.90.50.05+0.10.50=0.0225,2AS=0.90.50.87+0.10.380.5=0.4102AS1AS,2,,:(1)45,5,,,3.9/,195(2)8444CS=(844-813.8)/844=0.03,TS=0.1,S=0.50.03+0.50.1=0.0650,,S=0.065[0.025,0.625],12FIDICFIDIC34,WTO[1],.[M].:19934[2]...[M].:200012[3].[M].:19969[4].[J].1994~[5]FIDIC.[M].:1991[6].[M].:19955[7].[M].:199712[8].[M].:199611[9].[M].:199610[10].[M].:19969[11].[M].:19986[12],.[M].:1996[13],,.[M].:1997.1[14],.[M].:2001619-632[15].[J].20011010[16].[J].2001499[17].WTO[J].2001418-29[18],,.[J].2000310-14[19],.----[J].2000225-27[20],,.[J].20049163-164[21],.FIDIC[J].200412293-296[22].[J].20038[23].[M].:200010[24]WimBakens.InternationalTrendsinBuildingandConstructionResearch.JournalofConstructionEngineeringandManagement[J]vol.123,No.2,June1997:102-104[25]JanetR.Y