EJT 1096-1999 密封箱室密封性分级及其检验方法

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ICS13.280F79EJ/T1096—1999eqvISO10648—2:1994Containmentenclosures:Classificationaccordingtoleaktightnessandassociatedcheckingmethod1998-12-301999-04-01ISO10684-2:1994——ISO10648-2“”“”GB/T1.1—1993ABCDEF ISO   ISOISOISOISOISOIEC75%ISO10648-2ISO/TC85ISO10648“”ISO10648AF 1 EJ/T1108—1999//2 GB/T10627—89   EJ/T1108—1999 3 3.1  containmentenclosure3.2 Tf hourlyleakrate1hFVTf=F/VTfh14 Tf11000Pa250Pa415 5.15.25.3a1Tth1   115×104212.5×103310241011121b23c344HEPA5.1 F15.1.1 TfO2fvpmO2ivpmtmin300=60×100/206060min100/2020%5.1.2 1a 123102h101000vpmF[123]b c 100Pad GB/T10627—89e 5.1.3 100vpm250Pa1000PaO2itt30minO2f 62if2f10300×−=tOOT15.1.4 5.1.5 a3b1000Pac50Pa5.1.6 abc —— —— —— ——deA5.2 F[45]5.2.1 45.2.2 2a 0.1b 0.1;c 10Pad 10Pa5.2.3 1000Pa250Pa15min1h12 T       P1—P225.2.4 5.2.5 1ha30%b±0.3c100Pad11350Pa5.2.6 BCD3.2TftminP1PaPnPaT1KTnK601h60minθTKT=θ+27321000PaTf2.5×103h1250PaCB∆P∆TPaKDD5.3 F[67]5.3.1 3.25.3.2 3a3b4cdef )1(60n11nf−×=TPTPtTT—PF34R35.3.3 250Pa1000Pa45.3.4 5.3.5 10min5.3.6 abcdeE A5.11 ________________________________________________________________________________2 ________________________________________________________________________________________________________________________________________________________1.4m30.03m31.405m3a________________b____________3 20.7           20.820.9           20.8101000Pa  101000PaP=1000Pat=120min4 O2i=100vpmO2f=180vpm=2.0×104h15 EJ/T1096—1999/1                                                     B5.21 __________________________________________________________________________________________________________________________________________________________________  2 62i2ff10300×−×=tOOT610120100180300×−×=KPaPaPa10:00T1=293.01010001000p1=10000011:00Tn=292.9101020950pn=100070t=60min∆T=0.1∆p=+703 EJ/T1096—1999/2              C5.2 P1=100000PaPn=100070Pa∆P=+70PaT1=293.0K,Tn=292.9K,∆T=0.1Kt=60min)1(60n11nf−×=TpTptT)19.2921000000.293100070(6060−×××=-13h1004.1−×=Tf=1.04×103hEJ/T1096—1999/2              D5.21  ___________________          ______________________________________________        /____________________________________________        __________________________________________________2 12Pa20.019.9 0.1-34 Pa101000101020 20Pa-20 10:0011:0060minPa1000.095020.019.9A PaPaPa2Pa+        +           950   =     896        34 -    20 B A1PaPaPa   1000                  896     =         104    C B3 EJ/T1096—1999/2                E5.31 ______________________________________________________________________________________________________________________________________________________________________2  ×              V=3200m3v=100m3           3 4   100000104D=C=1.04×10-3= 1.04×10-3h-1h    1   :22.3   :22.3:250Pa :250Pa:22.5   :22.510min:101500Pa :101500PaQ=24m3/hvVQT−=f5 EJ/T1096—1999/3                F[1]NFM62-210,Containmentenclosures—Methodofcontroloftheleakrateperhour. Enclosuresofclasses1and2—Methodofmeasurementoftheincreaseoftheoxygenconcentration,AFNOR,1984.[2]NFX20-378,Gasanalysis—Oxygenanalysis:Electrochemicalmethodwithsolidelectrolyte,AFNOR,1979.[3]NFX20-379,Gasanalysis—Oxygenanalysis:Electrochemicalmethodswithliquidorgelledelectrolyte,AFNOR,1979.[4]Leaktestsforlowworkingpressurecontainers,AtomicEnergyCodeofPractice,AECP(R)5,1984.[5]DIN25412Teil2,Laboreinrichtungen—Handschuhkasten—Dichtheitsprufung,DIN,1988.[6]NFM62-211,Containmentenclosures—Methodofcontroloftheleakrateperhour—Enclosuresofclass3,AFNOR,1984.[7]NFM62-212,Containmentenclosures—Methodofcontroloftheleakrateperhour—Enclosuresofclass4,AFNOR,1984.[8]Containmentenclosures—Ventilation,Filtration:PMDSCollectionProtection-Manipulation-Detection-Safety,VolumeIV/1,CEA1),1988.  1)CEA:AtomicEnergyCentre CENFontenay-aux-Roses BP6 F-92265Fontenay-aux-Roses-France ____________________310024=13h1074.7−−×=

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