i(m)D(mm)0.510.49(m)L3.4920.2(m2)Ap=D2*/40.1963531.8p(m)p=D*1.5708413.1415956p(0.750.95)fsk(KPa)qp(KPa)0.50.85130300Ra1=p*sia*li+p*A*qp125.114Ra2cu*Ap/4Ra125.114cu(KPa)fcu4Ra/Ap2293.920fcuKPam(0.010.10)m=(fspk-*fsk)/(Ra/Ap-*fsk)0.1933de22de2=D2/m1.2932(m)1.00641m'0.1958(Ra)3500Ra(KN)spk(KPa)fspk=m*Ra/Ap+*(1-m)*fsk201.15(m)3.49(m)1siaKPapKPa10101527spk(KPa)2000.9