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ANSYS热应力分析例题实例1圆简内部热应力分折：有一无限长圆筒，其核截面结构如图13—1所示，简内壁温度为200℃，外壁温度为20℃，圆筒材料参数如表13．1所示，求圆筒内的温度场、应力场分布。该问题属于轴对称问题。由于圆筒无限长，忽略圆筒端部的热损失。沿圆筒纵截面取宽度为10M的如图13—2所示的矩形截面作为几何模型。在求解过程中采用间接求解法和直接求解法两种方法进行求解。间接法是先选择热分析单元，对圆筒进行热分析，然后将热分析单元转化为相应的结构单元，对圆筒进行结构分析；直接法是采用热应力藕合单元，对圆筒进行热力藕合分析。/filname,exercise1-jianjie/title,thermalstressesinalong/prep7$Et,1,plane55Keyopt,1,3,1$Mp,kxx,1,70Rectng,0.1,0.15,0,0.01$Lsel,s,,,1,3,2Lesize,all,,,20$Lsel,s,,,2,4,2Lesize,all,,,5$Amesh,1$Finish/solu$Antype,staticLsel,s,,,4$Nsll,s,1$d,all,temp,200lsel,s,,,2$nsll,s,1$d,all,temp,20allsel$outpr,basic,allsolve$finish/post1$Set,last/plopts,info,onPlnsol,temp$Finish/prep7$Etchg,ttsKeyopt,1,3,1$Keyopt,1,6,1Mp,ex,1,220e9$Mp,alpx,,1,3e-6$Mp,prxy,1,0.28Lsel,s,,,4$Nsll,s,1$Cp,8,ux,allLsel,s,,,2$Nsll,s,1$Cp,9,ux,allAllsel$Finish/solu$Antype,staticD,all,uy,0$Ldread,temp,,,,,,rthAllsel$Solve$Finish/post1/title,radialstresscontoursPlnsol,s,x/title,axialstresscontoursPlnsol,s,y/title,circularstresscontoursPlnsol,s,z/title,equvialentstresscontoursPlnsol,s,eqv$finish/filname,exercise1-zhijie/title,thermalstressesinalong/prep7$Et,1,plane13Keyopt,1,1,4$Keyopt,1,3,1Mp,ex,1,220e9$Mp,alpx,,1,3e-6$Mp,prxy,1,0.28MP,KXX,1,70Rectng,0.1,0.15,0,0.01$Lsel,s,,,1,3,2Lesize,all,,,20$Lsel,s,,,2,4,2Lesize,all,,,5$Amesh,1Lsel,s,,,4$Nsll,s,1$Cp,8,ux,allLsel,s,,,2$Nsll,s,1$Cp,9,ux,allALLSEL$Finish/solu$Antype,staticLsel,s,,,4$Nsll,s,1$d,all,temp,200lsel,s,,,2$nsll,s,1$d,all,temp,20allsel$outpr,basic,allsolve$finish/post1$Set,last/plopts,info,onPlnsol,temp/title,radialstresscontoursPlnsol,s,x/title,axialstresscontoursPlnsol,s,y/title,circularstresscontoursPlnsol,s,z/title,equvialentstresscontoursPlnsol,s,eqv$finish实例2冷却栅管的热应力分析图中为一冷却栅管的轴对称结构示意图，其中管内为热流体，温度为200℃，压力为10Mp,对流系数为110W／(m2•℃)；管外为空气，温度为25℃，对流系数为30w／(mz．℃)。栅管材料参数如表13—2所示，求栅管内的温度场和应力场分布。根据对称性，并在图示边界线段上施加对称边界约束，进行热应力分析求解。FINISH$/CLEA/filname,exercise2/title,thermalstressesinanaxisymmetricalpipe/prep7$et,1,plane13$Keyopt,1,1,4mp,ex,1,200e9$Mp,alpx,1,1.5e-5mp,prxy,1,0.3$mp,kxx,1,30rectang,0.12,0.16,0,0.07$rectang,0.16,0.4,0.025,0.045$rectang,0.38,0.4,0.015,0.055k,100,0.15,0.055$k,101,0.15,0.015aadd,all$numcmp,linelfillt,8,12,0.01$lfillt,7,9,0.01ldiv,9,0.8$ldiv,12,0.8L2tan,12,-6$L2tan,9,5al,15,16,17$al,18,19,20al,14,22,23$al,13,21,24aadd,1,2,4$aadd,5,6aadd,1,3$numcmp,lineesize,0.0025$wpstyle,,,,,,,,1csys,4$kwpave,100wprot,0,0,90$asbw,2wprot,0,90$asbw,3kwpave,101$asbw,4kwpave,16$wprot,0,-90$asbw,5kwpave,19$asbw,6kwpave,12$asbw,7amesh,1,3$amesh,5,8,3amap,4,15,16,18,17$amap,6,19,20,9,12allsel$wpstyle,,,,,,,,0csys,0$nsel,s,loc,y,0cp,1,uy,all$allsel$finish/solu$antype,staticSfl,3,pres,10e6$Sfl,3,conv,110,,200Lsel,s,,,4,18$Lsel,a,,,20,21Sfl,all,conv,30,,25$Lsel,s,,,17,20,3Dl,all,,symm$lsel,s,,,18,21,3Dl,all,,symm$allselOutpr,basic,all$Solve$Finish/post1$Set,last/title,temperaturecontoursPlnsol,temp/title,sumdisplamentlcontoursPlnsol,u,sum/title,radialstresscontoursPlnsol,s,x/title,axialstresscontoursPlnsol,s,y/title,circularstresscontoursPlnsol,s,z/title,equvialentstresscontoursPlnsol,s,eqv/expand,9,axis,,,10/view,1,1,1,1/title,temperaturecontoursPlnsol,temp/title,equvialentstresscontoursPlnsol,s,eqv$finish实例3两无限长平扳热膨胀分析：有两块厚度均为0.02mm的无限长平板1和2，受如图13—52所示约束。平板初始温度为20℃，求将其加热到800℃时平板内部的应力场分布(平板材料参数见表)。根据题意，忽略平板沿长度方向的端面效应，将问题简化为平面应变问题。在分析过程中取两平板的横截面建立几何模型，并选取plane13热一结构锅台单元进行求解。/filname,exercise3/title,thermalexpansionbetweentwoinfiniteflat/prep7$et,1,plane13$Keyopt,1,1,4mp,alpx,1,1.5e-5$mp,ex,1,1.0e11mp,prxy,1,0.25$mp,kxx,1,65mp,prxy,2,0.3$mp,ex,2,2.0e11mp,kxx,2,30$mp,alpx,2,2.5e-5rectng,0,0.1,0,0.02$rectng,0.1,0.3,0,0.02esize,0.02$mat,1$amesh,1$mat,2$amesh,2nummrg,all$numcmp,all/solu$antype,staticAutots,on$lsel,s,,,4,6,2Nsll,s,1$d,all,uxTref,20$bfunif,temp,800Allsel$solve/post1$Set,last/plopts,info,on/title,temperaturecontoursPlnsol,temp/title,sumdisplamentlcontoursPlnsol,u,sum/title,xdirectiondisplamentcontoursPlnsol,u,x/title,ydirectiondisplamentcontoursPlnsol,u,y/title,sumdirectiondisplamentcontoursPlnsol,u,sum/title,xdirectionstresscontoursPlnsol,s,x/title,ydirectionstresscontoursPlnsol,s,y/title,equvialentstresscontoursPlnsol,s,eqv$finish实例4包含焊缝的金属板热膨胀分析某一平板由钢板和铁板焊接而成，焊接材料为铜，平板尺寸为1×1×0.2，横截面结构如图13—68所示。平板初始温度为800℃，将平板放置于空气中进行冷却，周围空气温度为30℃，对流系数为110W／(m2．℃)。求10分钟后平板内部的温度场及应力场分布(材料参数见表134)。属于瞬态热应力问题，选择整体平板建立几何模型，选取solid5热一结构耦合单元进行求解。/filname,exercise4/title,thermalstressesinsecti*****includingweldingseam/prep7$et,1,plane13Keyopt,1,1,4$et,2,solid5Mp,alpx,1,1.06e-5$mp,kxx,1,66.6Mp,dens,1,7800$mp,c,1,460Mptemp,,30,200,400,600,800Mpdata,ex,1,,2.06e11,1.92e11,1.75e11,1.53e11,1.25e11Mpdata,prxy,1,,0.3,0.3,0.3,0.3,0.3Tb,bkin,1,5!指定材料模型Tbtemp,30$Tbdata,1,1.40e9,2.06e10Tbtemp,200$Tbdata,1,1.330e9,1.98e10Tbtemp,400$Tbdata,1,1.15e9,1.83e10Tbtemp,600$Tbdata,1,0.92e9,1.56e10Tbtemp,800$Tbdata,1,0.68e9,1.12e10MP,ALPX,2,1.75E-5$MP,KXX,2,383MP,DENS,2,8900$MP,C,2,390MPDATA,EX,2,,1.03E11,0.99E11,0.90E11,0.79E11,0.58E11MPDATA,PRXY,2,,0.3,0.3,0.3,0.3,0.3TB,BKIN,2,5TBTEMP,30$TBDATA,1,0.9E9,1.03E10TBTEMP,200$TBDATA,1,0.85E9,0.98E10TBTEMP,400$TBDATA,1,0.75E9,0