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2021()85401.A={x|-2x4}B={2345}AB=()A.{2}B.{23}C.{34}D.{234}2.z=2-iz(z+i)=()A.6-2iB.4-2iC.6+2iD.4+2i3.2()A.2B.22C.4D.424.f(x)=7sin(x-6)()A.(0,2)B.(2)C.(,32)D.(322)5.F1F2C:x29+y24=1MC|MF1|?|MF2|()A.13B.12C.9D.66.tan=-2sin(1+sin2)sin+cos=()A.-65B.-25C.25D.657.(a,b)y=ex()A.ebaB.eabC.0aebD.0bea8.612345611287()A.B.C.D.45205209.x1x2?xny1y2?ynyi=xi+c(i=12?n)c()A.B.C.D.10.OP1(cos,sin)P2(cos,-sin)P3(cos(+)sin(+))A(1,0)()A.|OP1|=|OP2|B.|AP1|=|AP2|C.OA?OP3=OP1?OP2D.OA?OP1=OP2?OP311.P(x-5)2+(y-5)2=16A(4,0)B(0,2)()A.PAB10B.PAB2C.PBA|PB|=32D.PBA|PB|=32112.ABC-A1B1C1AB=AA1=1PBP=BC+BB1[01][01]()A.=1AB1PB.=1P-A1BCC.=12PA1PBPD.=12PA1BAB1P452013.f(x)=x3(a?2x-2-x)a=14.OC:y2=2px(p0)FPCPFxQxPQOP|FQ|=6C15.f(x)=|2x-1|-2lnx16.20dm12dm110dm12dm20dm6dmS1=240dm225dm12dm10dm6dm20dm3dmS2=180dm24nnk=1Sk=dm267017.(10){an}a1=1an+1=an+1,n,an+2,n?(1)bn=a2nb1b2{bn}(2){an}2018.(12)ABA200B800A0.8B0.6(1)AXX(2)219.(12)ABCABCabcb2=acDACBDsinABC=asinC(1)BD=b(2)AD=2DCcosABC20.(12)A-BCDABDBCDAB=ADOBD(1)OACD(2)OCD1EADDE=2EAE-BC-D45A-BCDABCDEO321.(12)xOyF1(-170)F2(170)M|MF1|-|MF2|=2MC(1)C(2)Tx=12TCABPQ|TA|?|TB|=|TP|?|TQ|ABPQ22.(12)f(x)=x(1-xln)(1)f(x)(2)abbaln-abln=a-b21a+1be42021()85401.A={x|-2x4}B={2345}AB=()A.{2}B.{23}C.{34}D.{234}A={x|-2x4}B={2345}AB={x|-2x4}{2345}={23}B2.z=2-iz(z+i)=()A.6-2iB.4-2iC.6+2iD.4+2iz=2-iz(z+i)=(2-i)(2+i+i)=(2-i)(2+2i)=4+4i-2i-2i2=6+2iC3.2()A.2B.22C.4D.42l2?2=?ll=2222B4.f(x)=7sin(x-6)()A.(0,2)B.(2)C.(,32)D.(322)-2+2kx-62+2kkZ-3+2kx23+2kkZk=0k[-323](0,2)?[-323]A5.F1F2C:x29+y24=1MC|MF1|?|MF2|()A.13B.12C.9D.6F1F2C:x29+y24=1MC|MF1|+|MF2|=6|MF1|?|MF2|(|MF1|+|MF2|2)2=9|MF1|=|MF2|=3|MF1|?|MF2|9C6.tan=-2sin(1+sin2)sin+cos=()A.-65B.-25C.25D.65sin(1+sin2)sin+cos=sin(sin2+cos2+2sincos)sin+cos=sin(sin+cos)2sin+cos=sin(sin+cos)=sin2+sincossin2+cos2=tan2+tan1+tan25=4-21+4=25C7.(a,b)y=ex()A.ebaB.eabC.0aebD.0beay=exy=ex0y0x(a,b)x0(a,b)x(a,b)(a,b)(a,b)x0beaD8.612345611287()A.B.C.D.8(2,6)(3,5)(4,4)(5,3)(6,2)7(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)P()=16P()=16P()=566=536P()=666=16A.P()=0P()P()B.P()=136=P()P()C.P()=136P()P()D.P()=0P()P()B45205209.x1x2?xny1y2?ynyi=xi+c(i=12?n)c()A.B.C.D.AcABcBCD(yi)=D(xi+c)=D(xi)CDyi=xi+c(i=12?n)cxxmax-xminy(xmax+c)-(xmin+c)=xmax-xminDCD10.OP1(cos,sin)P2(cos,-sin)P3(cos(+)sin(+))A(1,0)()A.|OP1|=|OP2|B.|AP1|=|AP2|C.OA?OP3=OP1?OP2D.OA?OP1=OP2?OP3P1(cos,sin)P2(cos,-sin)P3(cos(+)sin(+))A(1,0)OP1=(cos,sin)OP2=(cos,-sin)OP3=(cos(+)sin(+))OA=(1,0)AP1=(cos-1,sin)AP2=(cos-1,-sin)Oxya,by=ex6|OP1|=cos2+sin2=1|OP2|=cos2+(-sin)2=1|OP1|=|OP2|A|AP1|=(cos-1)2+sin2=cos2+sin2-2cos+1=2-2cos|AP2|=(cos-1)2+(-sin)2=cos2+sin2-2cos+1=2-2cos|AP1||AP2|BOA?OP3=1cos(+)+0sin(+)=cos(+)OP1?OP2=coscos-sinsin=cos(+)OA?OP3=OP1?OP2COA?OP1=1cos+0sin=cosOP2?OP3=coscos(+)-sinsin(+)=cos[+(+)]=cos(+2)OA?OP1OP2?OP3DAC11.P(x-5)2+(y-5)2=16A(4,0)B(0,2)()A.PAB10B.PAB2C.PBA|PB|=32D.PBA|PB|=32A(4,0)B(0,2)ABx4+y2=1x+2y-4=0(x-5)2+(y-5)2=16(5,5)x+2y-4=0d=|15+25-4|12+22=115=11554PAB[1155-41155+4]115551155-411155+410PAB102ABBPBA(PP1PBAP2PBA)|BC|=(5-0)2+(5-2)2=25+9=34|PB|=|BC|2-42=18=32CDACD12.ABC-A1B1C1AB=AA1=1PBP=BC+BB1[01][01]()A.=1AB1PB.=1P-A1BCC.=12PA1PBPD.=12PA1BAB1PA=1BP=BC+BB1CP=BB1CP//BB1PCC1AB1PAB1+B1P+APPCC1AB1P5+2PC1AB1P22+1AB=1BP=BC+BB1B1P=BCB1P//BCABCP1P2xyABCPA1B1C17PB1C1B1C1//A1BCB1C1A1BCA1BCP-A1BCBC=12BCB1C1MM1M1MBP=12BC+BB1MP=BB1MP//BB1PM1MPM1A1M1B1C1A1M1B1BB1C1B1B=B1A1M1BB1C1CBM1?BB1C1CA1M1BM1A1PBPPMA1PBPCD=12CC1D1BB1DBP=BC+12BB1DP=BCDP//BCPDD1PD1ACEA1EBEBEACC1A1AD1?ACC1A1AD1BEACC1A1AD1A1EBEA1E=EBEA1E?A1BEAD1A1BEA1B?A1BEA1BAD1ABB1A1A1BAB1AD1AB1=AAD1AB1?AB1D1A1BAB1D1AA1BPA1BAB1PDBD452013.f(x)=x3(a?2x-2-x)a=f(x)=x3(a?2x-2-x)y=x3Ry=a?2x-2-xRy|x=0=a?20-20=a-1=0a=1114.OC:y2=2px(p0)FPCPFxQxPQOP|FQ|=6Cx=-32PP(p2p)kOP=2PQOPkPQ=-12PQy-p=-12(x-p2)y=0x=5p2|FQ|=65p2-p2=6p=3x=-32x=-32PP(p2p)Q(p2+6,0)PQ=(6,-p)PQOPPQ?OP=0p=3x=-32x=-3215.f(x)=|2x-1|-2lnx1ABCA1B1C1PABCA1B1C1MPM1ABCA1B1C1DED1P8f(x)=|2x-1|-2lnx(0,+0x12f(x)=|2x-1|-2lnx=-2x+1-2lnxf(x)(012]f(x)f(12)=-212+1-2ln12=2ln2x12f(x)=|2x-1|-2lnx=2x-1-2lnxf(x)=2-2x=2(x-1)xx(121)f(x)0f(x)x(1,+f(x)0f(x)x=1f(x)f(1)=21-1-2ln1=12ln2=ln4lne=1f(x)=|2x-1|-2lnx1116.20dm12dm110dm12dm20dm6dmS1=240dm225dm12dm10dm6dm20dm3dmS2=180dm245nnk=1Sk=240(3-n+32n)dm220dm34dm,10dm32dm,5dm3dm,52dm6dm54dm12dm5kk+12402kSk=240(k+1)2knk=1Sk=240nk=1k+12kTn=nk=1k+12k12Tn=nk=1k+12k+112Tn=nk=1k+12k-nk=1k+12k+1=1+(n-1k=1k+22k+1-nk=1k+22k+1)-n+12n+1=1+14(1-12n-1)1-12-n+12n+1=32-n+32n+1Tn=3-n+32nnk=1Sk=240(3-n+32n)5240(3-n+32n)67017.(10){an}a1=1an+1=an+1,n,an+2,n?(1)bn=a2nb1b2{bn}(2){an}20(1)a1=1an+1=an+1,nan+2,na2=a1+1=2a3=a2+2=4a4=a3+1=5b1=a2=2b2=a4=5bn-bn-1=a2n-a2n-2=a2n-a2n-1+a2n-1-a2n-2=1+2=3{bn}b1=23bn=2+3(n-1)=3n-1(2)(1)a2n=3n-1nN*a2n-1=a2n-2+2=3(n-1)-1+2=3n-2n2n=1a1=1a2n-1=3n-2nN*{an}{an}20a1+a2+...+a20=(a1+a3+?+a19)+(a2+a4+?+a20)9=10+10923+102+10923=300a1+a2+...+a20=(a1+a3+?+a19)+(a2+a4+?+a20)=(a1+a2+2+a3+2+?a18+2)+(b1+b2+b3+?+b10)=19+(b1+b2+b3+?+b9)+(b1+b2+b3+?+b10)=19+9(2+26)2+10(2+29)2=30018.(12)ABA200B800A0.8B0.6(1)AXX(2)(1)X020100P(X=0)=1-0.8=0.2P(X=20)=0.8(1-0.6)=0.32P(X=100)=0.80.6=0.48X0201000.20.320