北京市朝阳区2019~2020学年高三第一学期期末化学试卷【带答案】

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2019~2020901002020.1H1C12N14O16Na23Cl35.5Fe5642314421ABCD2A-2--2-BCD3ASO2BNH3CSiO2DFe2O34ACsOHKOHBH2OH2SCNaMgDNa2CO3NaHCO353NO2+H2O===2HNO3+NONAA22.4LNO23NAB36gH2O2NAC1molHNO3NAD11.2LNO5NA6ACl2HClH2SO4BNH4ClFeCl3CCH2=CH2CH3CH2OHKMnO4DCH3COOCH2CH3CH3COOHNa2CO37A2Cl-+2H2O===2OH-+H2+Cl2BNa2CO3CaSO4CaSO4(s)+CO2-3CaCO3(s)+SO2-4CFe+NO3+4H+===Fe3++NO+2H2ODBa(OH)2NaHSO4Ba2+Ba2OHHSO42-===BaSO4H2O8ABCDAgClAgI925H2O2CH4iiiiiiivvviHCOAH2O2Biii42232CHHOCHOHHOCivH2OHH2O2DviHCOOHH2O10H2C(s)+H2O(g)===CO(g)+H2(g)H1=+131.3kJmol-1CH4(g)+H2O(g)===CO(g)+3H2(g)H2=+206.1kJmol-1CO(g)+H2O(g)===CO2(g)+H2(g)H3ABH2CCH4(g)===C(s)+2H2(g)H=74.8kJmol-1DC(s)+CO2(g)===2CO(g)HH1H311Al(OH)3MnO2Na2CrO4A2H2O-4e-===O2+4H+BCrO2-4CAl(OH)3MnO2DCrO2-4Cr(OH)312YAXYZB1molX3molH2C1molY2molNaOHD13AMC15H10N2O2BCDNHCO14FeCl3ABCc(Fe3+)D581512H1A_______2BAB_______3C_______4D2D_______5EF_______6G32CHCHOH32CHCHONa_______aNabNaOHc3NaHCOGH32CHCHOH_______168H2C2O410.1molL-1H2C2O4pH=1.3_______2pHKOHpH=2.5_______0.1molL-1KHC2O4_______ac(K+)+c(H+)=c(HC2O4)+c(C2O42)+c(OH)bc(K+)c(HC2O4)c(C2O42)c(H2C2O4)cc(K+)=c(HC2O4)+c(C2O42)+c(H2C2O4)3Fe2++H2C2O4+xH2O?FeC2O4xH2O+2H+FeC2O4xH2OFeC2O4xH2Ox0.5400gKMnO40.1000mol1KMnO418.00mLFe3+CO2Mn2+FeC2O4xH2Ox=_______FeC2O4144gmol11712N2g+3H2g2NH3g?H1*NH3_______c_______?H______02N2H21.0L5molN215molH2NH3T1T2T3_______MK=_______3MV2+/MV+_____________________1812K2FeO41K2FeO4i_______iiFe3++OH-+ClO-==FeO42-++iiiNa2FeO4_______K2FeO42K2FeO4i.K2FeO4O2ii.K2FeO4KOH2iii.K2FeO4iK2FeO4_______K2FeO4pH_______3K2FeO4K2FeO4N2K2FeO4pHK2FeO4pH_____pH=4______pH8pH_______19.14NaHSO3CuCl2CuSO4x1molL-1CuCl22mLCuCl230s1molL-1CuSO42mLCuSO431SO2______________2SO2a:Cu2+c(H+)b:ClCu2+HSO3CuClc(H+)a_______bI_____H++HSO3-===SO2+H2O3ClCu2+KXU_______424Cu+Cu2+SO32-Cu+Cu2+Cu+_______Cu2+Cu2+_______2019~20202020.190100421434212345678910DABDCACBCD11121314DBBC5815121231,4456a1681H2C2O4?H++HC2O4HC2O4?C2O42-+H+2224242HCOOHHCOHObc3NH3H2OH+c(H+)Fe2++H2C2O4+xH2O?FeC2O4xH2O+2H+,FeC2O4xH2O217121*NNH+H2*N+NH32T1T2T37.3210-33abN2+6H++6MV+===2NH3+6MV2+181212Fe2++H2O2+2H+===2Fe3++2H2O210323Cl5H2O24K2FeO4+10H2O===4Fe(OH)3()+3O2+8KOHpH3pH8NH4+pH8pHK2FeO419.141SO2+I2+2H2O===SO42+2I+4H+2c(Cu2+)2Cu2++2Cl+HSO3+H2O===2CuCl+SO42-+3H+3NaCl,4Cu2O

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