2020年北京市高考适应性测试试题

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162020615012040104401i(i+2)A(1,2)B(1,2)-C(2,1)D(2,1)-2{2}Axx={1,0,1,2,3}B=-AB=A{0,1}B{0,1,2}C{1,0,1}-D{1,0,1,2}-3(0,)+A1yx=+B21yx=-C1()2xy=D2logyx=42()56fxxx=-+A{|2xx3}xB{|3xx-2}x-C{|23}xxD{|32}xx--5(2,1)xA22(2)(1)1xy-+-=B22(2)(1)1xy+++=C22(2)(1)5xy-+-=D22(2)(1)5xy+++=6sin(2)3yx=-sin2yx=A3B6C3D6261227A23B43C2D48(2,0)A(0,2)B-Pyx=PAB2PA1B2C3D49{}nannS*n?N1nnSS+{}naABCD10ABCDE36A5ABAB12BB5CBB18DBB1ABCDE1016910819720361105525112221xya-=(0)a0xy+=a=12(1,)m=a(2,1)=babm=1324yx=114ABC4a=5b=6c=cosA=ABC15()fx[1,1)-()gxR(2)()0gxgx-+=(0,1)x()()gxfx=()gx(1,5)-3()0fx-{|10}xx-53(0)0g=0yxO12114-1-466851614PABCD-2PDAD=PDDAPDDCABCD,MNADPDPAMNCPBMNC1714{}naqnnS312a=k2020kSk2q=12q=2q=-PABCNMD561814A,B,C7A,B,C1ABC150A,B,C114,16,153101191521()e(1)e2xafxxx=--0a()yfx=(0,(0))f()fx()fxA10111213141516B12131415161718C13141516171819662014C(0,1)A(0,1)B-23Cym=C,MNDANBDBM14-Dx2114111202122aaAaa??=????11122122,,,{1,2,,6}aaaa12{,,,}{1,2,,6}lSeee=?12leeelN*6lk?kk-1-kk-12,,,lkeee=0()SA?0A1e?1A1A2e?2A1lA-le?lAlA0()STA01215A??=????0A2?1A01336A??=????{1,3}S=0()STA0A0()STA4-

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